What is the confidence interval for a 100 ohm resistor with 10% tolerance?

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The discussion centers on calculating the 95% confidence interval for a 100 ohm resistor with a 10% tolerance. The user calculates the tolerance as 10 ohms and attempts to determine the standard deviation (sigma) needed for the confidence interval. They derive that sigma should be less than or equal to approximately 5.1 ohms to satisfy the confidence interval requirement. The final confidence interval is proposed as 100 ohms ± 10 ohms, but there is uncertainty about the correct interpretation of tolerance and its relation to sigma. Clarification on the definitions and calculations involved in determining the confidence interval is sought.
vptran84
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What is the 95% confidence interval for 100 ohm resister with 10% tolerence?

Here is my work so far, can someone please tell me if I am doing it wrong or right? Thank you in advance.

from table 95%: k = 1.96
100 * 0.1( which is the 10% tolerance) = 10

10 / sigma >= 1.96
Sigma <= 5.10204

confidence interval limits:
100ohm +- 1.96(5.10204ohms) = 100ohm +- 10ohms
 
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Maybe my definition of tolerance is wrong, but isn't 1 sigma = 10% * 100ohms = 10 ohms?

A 95% confidence interval would then be +/- 1.96 sigma.
 
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