Confirm a) & Solve b): Homework Help

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Homework Statement



http://img139.imageshack.us/img139/999/ksknl6.th.jpg http://g.imageshack.us/thpix.php

Could someone confirm that the a) part is correct, and if it is, then what is the next step? :)
And I am not exactly sure what to do in the b) part.

I would really appreciate if someone could help me out with this. :)

Thanks in advance.
 
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NO, (a) is not correct because you haven't answered the question! I think you have misunderstood what is asked. If you were asked to find [itex]^4\sqrt{16}[/itex], you wouldn't answer "161/4"!

Don't change from polar to rectangular form until after you have done the root! One important reason for using polar form for complex numbers is the fact that
[tex][r (cos(\theta)+ i sin(\theta)]^n= r^n(cos(n\theta)+ i sin(n\theta))[/tex]

For n= 1/4,
[tex](7(cos(\pi/2)+ i sin(\pi/2))^{1/4}= 7^{1/4}(cos(\pi/8)+ i sin(\pi/8))[/tex]
Also, since adding [itex]2\pi[/itex] to the argument doesn't change the complex number, and [itex]2\pi/4= \pi/2[/itex] another fourth root is
[tex]7^{1/4}(cos(\pi/4+ \pi/2)+ i sin(\pi/4+ \pi/2))[/tex]
yet another is
[tex]7^{1/4}(cos(\pi/4+ \pi)+ i sin(\pi/4+ \pi))[/tex]
and, finally,
[tex]7^{1/4}(coS(\pi/4+ 3\pi/2)+ i sin(\pi/4+ 3\pi/2))[/tex]

Those are the four fourth roots of [itex]7(cos(\pi/2)+ i sin(\pi/2))= 7i[/itex]
 
Edit: Shows what I know. Listen to HallsofIvy instead
 
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