- #1

thomas49th

- 655

- 0

f = 1, -1<t<0

f = cos(pi*t),0<t<1

f(t+2) = f(t)

To what value does this series converge when t=1

So I need to find the Fourier series expansion and set it equal to one. Sooooo

I found the DC Value to be 1/2. Then I found a_{n} = 0 as well. Is this correct. Can a = 0 despite the function not being odd?

Thanks

Thomas