Confirming the dimension of induced charge density of a dielectric

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The discussion centers on confirming the units of volume charge density (ρ) and surface charge density (σ) for a dielectric material. The equations provided show ρ and σ in relation to the electric field (E) and the dielectric constant (k). There is confusion regarding the gradient of k, which is dimensionless, yet its application in the equations affects the units of ρ. Clarification is sought on whether the professor is using Gaussian units, with a note that the gradient operator has units of 1/length. Understanding these units is crucial for accurately interpreting the relationships in dielectric materials.
patric44
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Homework Statement
confirm the dimension of induced charge density of a dielectric ρ and σ
Relevant Equations
ρ = -1/4πk E.grad(k)
hi guys
our professor asked us to confirm the units of volume charge density ρ and also the surface charge density σ of a dielectric material given by
$$
\rho = \frac{-1}{4\pi k} \vec{E}\cdot\;grad(k)
$$
$$
\sigma= \frac{-(k-1)}{4\pi} \vec{E_{1}}\cdot\;\vec{n}
$$
I am somehow confused about the units, shouldn't the gradiant of k (the dielectric constant ) be dimensionless.
but that will leave ρ as the same units of E, which is not true as ρ =C/m^3.
can someone clarify
 
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##k## is dimensionless, but grad(##k##) is not.

Is your professor using Gaussian units?
 
thanks, by careful looking at the gradient operator i can see that it has a unit of 1/length
 
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