Confused about this Optics problems Solution

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Homework Help Overview

The problem involves calculating the radii of the bright rings surrounding the Airy disc in the diffraction pattern produced by a large refracting telescope. The context is optics, specifically focusing on diffraction through a circular aperture and the associated equations.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster expresses confusion regarding the use of a specific wavelength (550nm) in the solution, noting that the problem does not provide this information. Some participants discuss the common practice of making reasonable assumptions when complete data is not available.

Discussion Status

Participants have engaged in clarifying the reasoning behind the choice of wavelength, with one suggesting that it is a typical value for visible light. The discussion appears to be productive, with participants exploring the implications of assumptions made in the problem.

Contextual Notes

There is a noted absence of specific information regarding the wavelength of light, which is crucial for the calculations. The original poster highlights this as a point of confusion, prompting further discussion on the necessity of assumptions in real-world scenarios.

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Homework Statement


The Lick Observatory has one of the largest refracting telescopes, with an aperture diameter of 36 in. and a focal length of 56 ft. Determine the radii of the first, second, and third bright rings surrounding the Airy disc in the diffraction pattern formed by a star on the focal plane of the objective.

Homework Equations


\frac{\pi}{\lambda}Dsin\theta=\gamma
Where \gamma is either the maxima (bright fringes) or minima (dark fringes) of the bessel function which occurs in the solution to the diffraction through a circular aperture.
r=f \theta
Where f is the focal length.
Maxima of Gamma function: 5.136,8.417,...

The Attempt at a Solution


This is not an attempt, this is part of the actual solution. I do not understand a certain aspect of it though.

So using the first equation above and solved for sine. I came into a problem though. The problem doesn't give the wavelength! The solution just says..
"Thus for wavelength of 550nm..."
And then they plug it in. Where did this come from?!

Thanks :D
 
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550nm is green light - right in the middle of the visible spectrum and thus in the middle of the fringes/rings.

This sort of thing is common - IRL you are unlikely to have all the information you need to do a calculation right then and there. It may be difficult to get a figure too. So you have to make a reasonable guess. If you knew the spectra of the star in question, you would pick a different wavelength perhaps but you are only told that it is visible.
 
Thank you very much! That makes perfect sense :]
 
No worries then - have fun :)
 

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