Confused About Transformation of x: Help Needed!

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SUMMARY

The transformation from the expression x = Asin(ωt) + Bcos(ωt) to x = Rsin(ωt + φ) is achieved through the use of trigonometric identities. Specifically, R is defined as R = √(A² + B²), with cos(φ) = A/R and sin(φ) = B/R. This transformation is closely related to representing signals in the complex plane, where the expression v(t) = A[cos(ωt) + jsin(ωt)] is utilized. The addition formula for sine is applied to derive the new expression, allowing for a clear comparison of coefficients to identify A and B.

PREREQUISITES
  • Understanding of trigonometric identities, particularly the sine addition formula.
  • Familiarity with complex numbers and their representation in the complex plane.
  • Knowledge of polar coordinates and their relationship to Cartesian coordinates.
  • Basic calculus concepts related to wave functions and signal processing.
NEXT STEPS
  • Study the derivation of the sine addition formula in detail.
  • Explore the representation of signals in the complex plane using complex exponentials.
  • Learn about polar coordinates and their applications in physics and engineering.
  • Investigate the implications of signal transformations in Fourier analysis.
USEFUL FOR

Students and professionals in physics, engineering, and mathematics who are working with wave functions, signal processing, or complex analysis will benefit from this discussion.

ElDavidas
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Not sure exactly where to post this, but I don't see where this is coming from:

x = Asin \omega t + Bcos \omega t

to

x = Rsin(\omega t + \phi)

where

R = \sqrt {A^2 + B^2} and cos \phi = A/R and sin \phi = B/R

I'd be grateful if someone could point out what is going is on here.
 
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That's close to what you use for representing a signal in the complex plane:

v(t) = A[ cos(wt) + jsin(wt) ]

where you draw a circle of radius A, and horizontal and vertical axes centered on the circle. The horizontal axis is the real axis, and the real Acos(wt) component is projected onto it. The vertical axis is the imaginary component axis, and has the jAsin(wt) component projected onto it.

But your equations are slightly different -- where do they come from?
 
Use the addition formula of sin(a+b) on your new sine function.

\begin{array}{l}<br /> \sin \left( {\alpha + \beta } \right) = \sin \alpha \cos \beta + \sin \beta \cos \alpha \\ <br /> R\sin \left( {\omega t + \phi } \right) = R\cos \phi \sin \omega t + R\sin \phi \cos \omega t \\ <br /> \end{array}

Then identify the coefficients by comparing this to the initial expresseion, to match with A and B.
Notice the similarity with polar coördinates once you set up the equations, if you've seen those.
 

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