Confusing speed of man in moon question

In summary, a superman weighing 70kg jumps from the moon to Earth in 10sec and is moving at something like 15% of the speed of light. Considering gravity, he reaches the Earth in about 10s, but if you neglect to specify which bit of the Earth he lands on, the error is smaller than the error in neglecting to account for the moon's gravity.
  • #1
thedudereturns
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Consider a man having superpower,weighing 70 kg jumping from moon to reach Earth in 10sec..what's the speed at which he travels..considering gravity etc...
 
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  • #2
thedudereturns said:
from moon to reach Earth in 10sec..what's the speed at which he travels..considering gravity etc...
Gravity won't do much at that speed over this short period.
 
  • #3
A.T. said:
Gravity won't do much at that speed over this short period.
So is it simple d/t or do we have to consider anything else ..he is jumping...to Earth from moon
 
  • #4
thedudereturns said:
So is it simple d/t or do we have to consider anything else ..he is jumping...to Earth from moon
Ignoring all of the impossibilities, yes. It's simple d/t. He's moving at something like 15% of the speed of light.
 
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  • #5
and over 10s gravity adds about 14m/s. You get more error by not specifying which bit of the Earth he lands on.
 
  • #6
CWatters said:
and over 10s gravity adds about 14m/s. You get more error by not specifying which bit of the Earth he lands on.
Pardon me ..didn't quite understood what you said...please do explain
 
  • #7
thedudereturns said:
Pardon me ..didn't quite understood what you said...please do explain
Understand*
 
  • #8
thedudereturns said:
Pardon me ..didn't quite understood what you said...please do explain
The man is traveling in the neighborhood of 40 million meters per second. Most of that time will be spent far from the Earth and far from the moon where the acceleration from gravity is low. @CWatters has done some work and obtained an estimate of 14 meters/sec2 for average acceleration over the ten second interval.

As a crude estimate, that acceleration would amount to about a one part per million discrepancy in velocity. Maybe three parts per million if you are careless in the estimate. Three parts per million of the 400,000 km distance to the moon is about 1.2 km. There are mountains on the Earth taller than that. So the error from neglecting the acceleration is smaller than the error in neglecting to specify a landing spot.

[Note that the radius of the Earth is 6000 km. It's not just how high a mountain you land on. Whether you land dead center or nearer the horizon is even more important].
 
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  • #9
CWatters said:
You get more error by not specifying which bit of the Earth he lands on.
Which is nothing compared to the variation in the distance between the Earth and the Moon.
 
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  • #10
jbriggs444 said:
Note that the radius of the Earth is 6000 km. It's not just how high a mountain you land on. Whether you land dead center or nearer the horizon is even more important

The location of the moon in its' orbit makes even more difference - about 45,000km between apogee and perigee...
 
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  • #11
So this superman accelerates from 0 to 4e7m/s in the distance of extending his legs and body. Say his center of mass moves 1m. The acceleration lasts 50ns. Let's say his mass is 100kg. That requires a force of 8e16N imparting an energy of 8e16J. That assumes the moon outweighs him by a very large margin (it does) and that the moons surface can take the massive impact (it can't!)

Rather than accelerating toward the Earth most of superman's energy will go into putting a very large crater in the moon. How big? Let's picture an asteroid colliding at the much more usual collision speed of 10 m/s. For the collision to have the same energy the asteroid would have to weigh 1.6e15 kg which is the mass of an asteroid about 20km in diameter. Good thing superman attempted this jump from the moon. If he tried it on Earth we'd all go the way of the dinosaurs!
 
  • #12
This reminds me of "The man in the moon came down too soon and asked the way to Norwich ...".
 
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  • #13
The 14m/s figure I mentioned isn't really valid. It's the velocity you reach if you fall, starting from rest and accelerating at 9.8m/s/s, for 10s. So it's the most that gravity could add (I think).
 
  • #14
PeroK said:
This reminds me of "The man in the moon came down too soon and asked the way to Norwich ...".
You turn right off the M11 motorway and drive about 1 hr in NE direction if you started in London
It doesn't rhyme though.
 
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1. What is the "speed of man" in the moon question?

The "speed of man in the moon question" refers to the common misconception that the speed at which a person jumps on Earth would be the same as their speed if they were to jump on the moon. This is due to the assumption that the moon's gravity is the same as Earth's, when in fact it is about one-sixth of Earth's gravity.

2. Why is the speed of man on the moon different from on Earth?

The speed of a person on the moon is different from on Earth because of the difference in gravitational pull. The moon's gravity is much weaker than Earth's, so objects and people will fall at a slower rate on the moon compared to Earth.

3. How does the speed of man on the moon affect space travel?

The lower gravity on the moon actually makes it easier for spacecraft to land and take off compared to Earth. However, once in space, the speed of a spacecraft is not affected by the moon's gravity because it is already in a state of constant motion.

4. What is the actual speed of a person on the moon?

The actual speed of a person on the moon depends on many factors, such as their initial force and angle of jump, as well as the moon's gravity. However, the average speed of a person on the moon is about 1.6 meters per second, compared to about 9.8 meters per second on Earth.

5. Why is it important to understand the speed of man on the moon?

Understanding the speed of a person on the moon is important for many reasons. It helps scientists and engineers design and plan for space missions, as well as understand the physical differences between Earth and the moon. It also helps dispel common misconceptions and promotes scientific literacy.

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