zn5252 Messages 71 Reaction score 0 Thread starter Dec 2, 2012 #1 hello, Please see attached excerpt of a solution to a problem. I do not understand why the result obtained is to second order ? (this is a diffusion equation they say) Please let me know if you would need more info. Thanks, Attachments Screenshot.png 16.3 KB · Views: 425
hello, Please see attached excerpt of a solution to a problem. I do not understand why the result obtained is to second order ? (this is a diffusion equation they say) Please let me know if you would need more info. Thanks,
HallsofIvy Science Advisor Homework Helper Messages 42,895 Reaction score 983 Dec 2, 2012 #2 What does "at n- 1" mean?
zn5252 Messages 71 Reaction score 0 Dec 2, 2012 #3 n-1 means at the step which is prior to step n where n is the number of boosts . I have attached the first paragraph for more details. Attachments Screenshot-1.png 11.3 KB · Views: 446
n-1 means at the step which is prior to step n where n is the number of boosts . I have attached the first paragraph for more details.
haruspex Science Advisor Homework Helper Insights Author Gold Member Messages 42,946 Reaction score 10,550 Dec 2, 2012 #4 It's because the first order differences will cancel out: f(x+dx) + f(x-dx) ≈ f(x) + f'(x)dx + f''(x)dx2/2 + f(x) - f'(x)dx + f''(x)dx2/2 = 2f(x) + f''(x)dx2
It's because the first order differences will cancel out: f(x+dx) + f(x-dx) ≈ f(x) + f'(x)dx + f''(x)dx2/2 + f(x) - f'(x)dx + f''(x)dx2/2 = 2f(x) + f''(x)dx2