What is the velocity distribution of evaporating H2O molecules? It can not be Maxwellian.
Good question. A bit of google-foo yields:
Thank you for the references. They deal with rather specific issues of this general question. I would like to
reframe it in more simple terms. A Maxwellian distribution results when freely moving particles interact
elastically. The question can be posed as follows - is the evaporation of an H2O molecule elastic?
Is it a two particle interaction? If not, can the distribution of evaporating molecules be Maxwellian?
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