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Well, we say they are "dressed". We don't say how. Non-judgemental and all that.hutchphd said:The particles are in drag
Well, we say they are "dressed". We don't say how. Non-judgemental and all that.hutchphd said:The particles are in drag
1. There are forces, but in quantum physics they do not manifest in the same way as they do in classical physics. See e.g. the Ehrenfest theorem.hutchphd said:So
I need to learn QFT.......
- there are no "forces"
- there is no "finite time"
- The particles are in drag
I read it as "dressed particles"/"non-naked particles".Demystifier said:3. I have no idea what "particles are in drag" is supposed to mean, but it sounds to me as a manifestation of a force (see 1. above).
It depends on, how you define "forces". I'd say there are no forces in relativistic physics, because there are only local interactions through fields. For me a "force" is a Newtonian action-at-a-distance concept, but that's a matter of how you define words. Physicists are often pretty sloppy with that ;-)).Demystifier said:1. There are forces, but in quantum physics they do not manifest in the same way as they do in classical physics. See e.g. the Ehrenfest theorem.
That's true. It's, however, a matter of time scales. To have a particle interpretation you need to be sufficiently close to a situation, where the fields become asymptotically free. "Interpolating fields" (in the Heisenberg picture) generally don't admit a particle interpretation.Demystifier said:2. There is finite time, all experiments are done during finite times. But these times are long compared to typical times during which the scattering interaction is significant, so calculations are simpler when the long time is approximated with infinite time.
I guess it's meant "interpolating field".Demystifier said:3. I have no idea what "particles are in drag" is supposed to mean, but it sounds to me as a manifestation of a force (see 1. above).
Foundational issues don't play much of a role as far as the hard scientific facts are concerned. A measurement is done in the lab with detectors, not on the desk of the theoretician.Demystifier said:First one needs to properly learn QM. The crucial chapters are
a) axioms of QM, the role of measurement
I think the trick to really understand relativistic QFT is to really understand the representation of the Poincare group in terms of local quantum fields. For the intuitive concepts the best book I know isDemystifier said:b) time evolution in Schrödinger, Heisenberg and Dirac (interaction) picture
c) quantum scattering theory
After that, QFT should be easy at the conceptual level, while the new difficulties are mostly technical.
I would say "dressed particles" are rather the "true asymptotic free states" also known as "infra particles", i.e., The naked free particle + the "cloud of soft photons" around them (for QED).gentzen said:I read it as "dressed particles"/"non-naked particles".
By the way, I guess hutchphd's comment is tongue in cheek, at least partly. I guess he is more experienced with QFT than me, even so of course he is far below your level, or that of vanhees71 or A. Neumaier.
Sure. What I mean by force in relativistic field theory is best explained on the example of Klein-Gordon equation ##\ddot{\phi}-\nabla^2\phi+m^2\phi=0##. It can be written asvanhees71 said:It depends on, how you define "forces". I'd say there are no forces in relativistic physics, because there are only local interactions through fields. For me a "force" is a Newtonian action-at-a-distance concept, but that's a matter of how you define words. Physicists are often pretty sloppy with that ;-)).
It's a force on the field. If you think of field as a continuum limit originating from a lattice of atoms (emergent field from a condensed matter point of view), then the force on the field originates from forces on particles. Or even without such a condensed-matter point of view, thinking of it as force is helpful to understand how macroscopic forces on macroscopic bodies emerge from field theory. In particular, I have used such a point of view in my analysis of Casimir force: https://arxiv.org/abs/1605.04143vanhees71 said:This is not a force on a particle. I've never seen anybody calling this a force.
Well I think I know (or at least once knew!) the three prereqs you indicate but I never had a formal course in QFT and my (admittedly half-hearted) attempts to learn it have not caught fire. Could be I'm juuust tooo daamned old.Demystifier said:After that, QFT should be easy at the conceptual level, while the new difficulties are mostly technical.
May I ask, how old?hutchphd said:Well I think I know (or at least once knew!) the three prereqs you indicate but I never had a formal course in QFT and my (admittedly half-hearted) attempts to learn it have not caught fire. Could be I'm juuust tooo daamned old.

I am 71.Demystifier said:May I ask, how old?![]()
A very nice paper is:Haborix said:Very nice response, thank you for sharing! Do you have any suggestions for references that you think someone coming more from the physics side of QFT, as opposed to the math side, could read as an introduction to these finite time problems? But I'd be happy to know of more mathematical introductions also.
Wow, we get to meet celebs on this forum.meopemuk said:There is an approach called "dressed particle" QF....
Eugene.
Note that this approach does not produce an actual Hamiltonian evolution. The "unitary" evolution produced does not obey:Demystifier said:Title: Quantum Field Theory with Finite Time Interval: Application to QED
Does "true" evolution mean unitary evolution? But you can't describe the real world with unitary evolution alone. When you apply quantum theory, at some point you have to introduce "measurements" and the Born rule.LittleSchwinger said:Note that this approach does not produce an actual Hamiltonian evolution. The "unitary" evolution produced does not obey:
##U(t_{3},t_{1}) = U(t_{3},t_{2})U(t_{2},t_{1})##
Hence it's an approximation of the true time evolution breaking some of the true evolution's properties.
The authors of this work used the "standard" Lagrangian of QED in equation right after eq. (2.56). I have two major issues with their approach:Demystifier said:Title: Quantum Field Theory with Finite Time Interval: Application to QED
I've seen various views of renormalization, but I have never seen a claim before that this is the whole point of renormalization. In particular, lattice QCD also uses renormalization, but time (described on a finite 4D lattice) is finite.meopemuk said:the whole point of renormalization is to fix time evolution in the infinite time interval
I was talking about renormalization in the context of removing UV divergences from the S-matrix of QED as explained by Tomonaga, Schwinger, Feynman and Dyson.Demystifier said:I've seen various views of renormalization, but I have never seen a claim before that this is the whole point of renormalization. In particular, lattice QCD also uses renormalization, but time (described on a finite 4D lattice) is finite.
But infinite time gives rise to IR divergences, not UV divergences.meopemuk said:I was talking about renormalization in the context of removing UV divergences from the S-matrix of QED as explained by Tomonaga, Schwinger, Feynman and Dyson.
Eugene.
S-matrix is a mapping from (free) states in the remote past to (free) states in the distant future. So, basically S-matrix can be regarded as a result of integrating the time evolution in an infinite time interval.Demystifier said:But infinite time gives rise to IR divergences, not UV divergences.
I learned about it from this nice relatively recent paper by Holmfrodur Hannesdottir and Matthew Schwartz: https://arxiv.org/abs/1911.06821vanhees71 said:A bit more to the points is, I think, the idea of "infraparticles" in QED, i.e., to use the "true asymptotic free states" rather than naive "plane waves". The point is that in QED the photon is massless, and the asymptotic free states are in fact not plane waves due to the long-rangedness of the em. interaction (aka the masslessness of the photon). That solves the IR problems in a physical way. A very pedagogic paper about this is
P. Kulish and L. Faddeev, Asymptotic conditions and infrared
divergences in quantum electrodynamics, Theor. Math. Phys.
4, 745 (1970), https://doi.org/10.1007/BF01066485
or the series of papers by Kibble
T. W. B. Kibble, Coherent Soft-Photon States and Infrared
Divergences. I. Classical Currents, Jour. Math. Phys. 9, 315
(1968), https://doi.org/10.1063/1.1664582
T. W. B. Kibble, Coherent Soft-Photon States and Infrared
Divergences. II. Mass-Shell Singularities of Green’s Functions,
Phys. Rev. 173, 1527 (1968),
https://doi.org/10.1103/PhysRev.173.1527.
Kibble:1969ep[Kib68b]T. W. B. Kibble, Coherent Soft-Photon States and Infrared
Divergences. III. Asymptotic States and Reduction Formulas,
Phys. Rev. 174, 1882 (1968),
https://doi.org/10.1103/PhysRev.174.1882.
Kibble:1969kd [Kib68c] T. W. B. Kibble, Coherent Soft-Photon States and Infrared
Divergences. IV. The Scattering Operator, Phys. Rev. 175,
1624 (1968), https://doi.org/10.1103/PhysRev.175.1624.
This is a very reasonable question that I had puzzled over for a long time before understanding what actually happens.physwiz222 said:I am confused about Scattering in QED [...] why only cross sections and decay rates are computed. [...] does anyone calculate the actual evolution of the field states or operators themselves like how the particles and fields evolve throughout a scattering process not just asymptotic times.
Yes, but theorists would work harder to better develop it, if experimentalists were able to measure it.A. Neumaier said:Thus the reason why textbooks are silent about the temporal evolution is because theory is not developed enough to be able to say more than trivialities about it.
It's true that there are many mathematical problems unsolved in QFT. However, one must also say that in the vacuum QFT the calculation of the time-evolution (the initial-value problem) is pretty useless since there are no observables it depicts.A. Neumaier said:Thus the reason why textbooks are silent about the temporal evolution is because theory is not developed enough to be able to say more than trivialities about it.
No, in fact that's the point. Time evolution in QED is not unitary, but a contractive Markovian process. This is at the non-perturbative level. Perturbatively time evolution is unitary.WernerQH said:Does "true" evolution mean unitary evolution?