Confusion regarding cos or sin

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SUMMARY

The discussion centers on the confusion surrounding the application of trigonometric functions, specifically why sine (sin) is used for the vertical component (Fy) and cosine (cos) for the horizontal component (Fx) in force analysis. Participants emphasize that the definitions of sine and cosine are based on the orientation of the angle in a right triangle, where sine corresponds to the opposite side and cosine to the adjacent side. The importance of memorizing these definitions and correctly identifying the sides of the triangle in relation to the angle is crucial for solving physics problems accurately.

PREREQUISITES
  • Understanding of basic trigonometric functions (sine and cosine)
  • Familiarity with right triangle properties
  • Knowledge of force components in physics
  • Ability to interpret diagrams related to trigonometric functions
NEXT STEPS
  • Study the definitions and applications of sine and cosine in trigonometry
  • Practice identifying opposite and adjacent sides in various triangle configurations
  • Review force component calculations in physics problems
  • Explore visual aids and videos that explain trigonometric functions in detail
USEFUL FOR

This discussion is beneficial for students preparing for physics exams, particularly those struggling with the application of trigonometric functions in force analysis. It is also useful for educators seeking to clarify these concepts for their students.

joker2014
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Homework Statement


I have the solution and everything, I'm just confused why they use cos for Fy and sin for Fx ...

Homework Equations


I've always known Fx=Fcos and Fy=Fsin .. but now I am getting to different problems and it confuses me

The Attempt at a Solution


I read many posts and answers such as "take sin as opposite to theta" but I can't understand... I will apreciate if you could easily put this into brain! check image for example , if you got videos that help please share i have an exam tomorroW
 

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It depends on the way you define the angle.

For the side that is opposite to the angle, you need the sine, for the side next to the angle you need the cosine. That's just the definition of the two (more precise: one possible definition). No logic behind it, just one of the few things you have to learn by heart.
 
mfb said:
It depends on the way you define the angle.

For the side that is opposite to the angle, you need the sine, for the side next to the angle you need the cosine. That's just the definition of the two (more precise: one possible definition). No logic behind it, just one of the few things you have to learn by heart.
can you explain your concept using the attached image pls?
 
joker2014 said:
can you explain your concept using the attached image pls?
This is the image you should memorize:

http://demo.activemath.org/ActiveMath2/LeAM_calculusPics/TrigFunctionsTriangle.png?lang=en​
 
Last edited by a moderator:
I know this and memorized this, even using SOH CAH TOA,, but I can't apply it to the problems I am getting now
 
joker2014 said:
I know this and memorized this, even using SOH CAH TOA,, but I can't apply it to the problems I am getting now
Well, why don't you take F1 in Prob. 2-145 and identify the parts of the force triangle? IOW, what are the components of F1 ?
 
well using the concept of "use sine for side opposite to angle" .. then Id say Fx=30sin30 and also Fy=30sin30 ... becausee I take the side and it turns out to be opposite to the angle... this is how I'd solve it and its wrong anyways
 
joker2014 said:
well using the concept of "use sine for side opposite to angle" .. then Id say Fx=30sin30 and also Fy=30sin30 ... becausee I take the side and it turns out to be opposite to the angle... this is how I'd solve it and its wrong anyways

I can't make out your justification here.

Clearly, the diagram for F1 shows that the angle is 30°. The hypotenuse of the triangle is the line of action with the arrow at the end. There are only two other sides to the triangle, and there can be only one side which is opposite of the 30° angle and one side which is adjacent.

Hint: the opposite side to the angle is the side which doesn't form the angle. The adjacent side is that side (not the hypotenuse) which does form the angle.
 
joker2014 said:
I know this and memorized this, even using SOH CAH TOA,, but I can't apply it to the problems I am getting now

If you are familiar with the drawing Steamking posted then just turn it around until the arrangement matches what's on the problem statement. For example..

Angles.png
 

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