- #1

foo9008

- 678

- 4

## Homework Statement

water flows in an elbow was aligned horizontally , of angle 135 degree . If the water volume is section 1 and 2 is 0.2m^3 , the elbow is 12kg , flow rate is 0.4(m^3)/s , find the resultant force

## Homework Equations

## The Attempt at a Solution

i found x and y component of the force

for x-component , i have P1A1 - P2A2costheta -Fx =

**ρQ(v1-v2costheta)**

(150x10^3)(pi)[(400x10^-3 / 2 )^2 ] -(90x10^3)(pi)[(200x10^-3 /2 )^2 ]

Fx= 19170N to the left

for y component ,

P2A2sintheta +Fy -12(9.81) =

(90x10^3)

(150x10^3)(pi)[(400x10^-3 / 2 )^2 ] -(90x10^3)(pi)[(200x10^-3 /2 )^2 ]

**(cos-45)**-Fx = (1000)(0.4)( 3.18- 12.7cos-45)Fx= 19170N to the left

for y component ,

P2A2sintheta +Fy -12(9.81) =

**ρQ(v2 sin theta)**(90x10^3)

**(pi)[(200x10^-3 / 2 )^2 ]****(sin-45) +Fy****-12(9.81) =****(1000)(0.4)(12.7sin45)**

Fy = 1711 N upwards

FR = 19246NFy = 1711 N upwards

FR = 19246N