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cnrrehab
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Homework Statement
The area A of a triangle with sides of lengths a and b enclosing an angle of measure [itex]\theta[/itex] is:
A=1/2 ab sin ([itex]\theta[/itex])
How is dA/dt related to d[itex]\theta[/itex]/dt if side a and side b is constant?
Homework Equations
The Attempt at a Solution
I am pretty sure that I need to differentiate with respect to t. So since the 1/2, a and b are constant, would I just take the derivative of sin [itex]\theta[/itex], so it would look like:
dA/dt= 1/2 ab * cos [itex]\theta[/itex]? I feel like I am missing something. If I am using the chain rule, would I add d[itex]\theta[/itex]/dt at the end? I am a little confused. Thanks in advance for any help as I am taking Calculus over the summer, and it is not easy.