Conservation law associated with the symmetry of a helix

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SUMMARY

The discussion centers on the conservation law associated with the symmetry of an infinite homogeneous cylindrical helix as presented in Landau’s mechanics. The conserved quantity is derived from the Lagrangian, which remains unchanged under a rotation of dΦ and a translation of hdφ/(2π), leading to the conservation of Mz + hPz/(2π). Here, M and P represent angular and linear momenta, respectively. The orientation of the helix—right-handed or left-handed—affects the conservation law, specifically altering it to Mz - hPz/(2π) for a left-handed helix.

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Hiero
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In a problem in Landau’s mechanics (end of section 9) he asks for the quantity conserved in the field of “an infinite homogenous cylindrical helix.”

The solution is that the Lagrangian is unchanged by a rotation of dΦ together with a translation of hdφ/(2π) (about and along the symmetry axis) where h is the pitch of the helix. This implies that Mz+hPz/(2π) is conserved where M and P are the angular and linear momenta and _z means the component along the symmetry axis.

It’s a very nice example of Noether’s theorem, but I have one question:

Is he silently assuming that the helix is right handed? Surely for a left handed helix the conservation law would be Mz-hPz/(2π), right?

Just want to make sure I’m understanding that correctly because Landau never mentions the orientation of the helix, but I think it matters.

Thanks.
 
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A left-handed helix would have a negative ##h##.

Edit: In other words, what matters is the definition of the symmetry as the transformation of ##d\phi## in the angle being accompanied by the translation ##h\, d\phi/(2\pi)##.
 
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Orodruin said:
A left-handed helix would have a negative ##h##.
When I looked up “helix pitch” I just found that it was the step height, but I guess some people also encode the orientation like this.

Thanks Orodruin!
 

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