Conservation of angular momentum

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The discussion revolves around a physics problem involving conservation of angular momentum after a ball strikes a rod. The initial angular momentum of the system is calculated using the ball's mass and velocity, leading to the equation MvD = -3MvD/4 + IW. The user initially miscalculated the final angular velocity of the rod, arriving at W = 7MvD/I. Upon reevaluation, they recognized their error and acknowledged that the correct answer is W = 7MvD/4I. The conversation highlights the importance of careful algebraic manipulation in physics problems.
Mohammeddev
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Homework Statement


A rod of length D sits at rest on a friction less table. A ball of mass M strikes the end of the rod with a speed V and rebounds with a speed 3v/4 causing the rod to rotate counterclockwise around a fixed axis at one end. The rotational inertia of the rod is I

Homework Equations


Li = Lf

The Attempt at a Solution


the question is :
What is the angular velocity ω of the rod after the collision?
We know that the initial angular momentum is equal to the final angular momentum so i started with the ball because it's the only object in our system that has initial angular momentum:

MvD = -3MvD/4 + IW

doing some algebra:
MvD * 4 = -3MvD + IW
4MvD + 3MvD = IW
7MvD = IW
W = 7MvD/I

But the correct answer is :
7MvD/4I
my question where did the 4 come from ?
is my math Wrong ?
 
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Mohammeddev said:
MvD = -3MvD/4 + IW

doing some algebra:
MvD * 4 = -3MvD + IW
Check what you are doing to go from the first equality to the second.
.
 
DrClaude said:
Check what you are doing to go from the first equality to the second.
.
Okay now i realized the mistake i made :cry: Thank you for making me recheck my answer i was so convinced that khan academy is wrong in this one !
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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