Conservation of energy: mass-spring system

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SUMMARY

The discussion focuses on a mass-spring system involving a 1 kg block on a frictionless surface connected to a spring with a spring constant of 50 N/m and a 0.45 kg dangling mass. When the mass is released, energy conservation principles dictate that the gravitational potential energy of the falling mass converts into spring potential energy. The calculated distance the mass falls before stopping is 0.176 m, as confirmed by the energy conservation law applied to the system.

PREREQUISITES
  • Understanding of energy conservation principles in physics
  • Familiarity with spring mechanics, specifically Hooke's Law
  • Knowledge of gravitational potential energy calculations
  • Ability to manipulate algebraic equations to solve for unknowns
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  • Study the derivation of the conservation of energy equation in mechanical systems
  • Learn about Hooke's Law and its applications in spring systems
  • Explore gravitational potential energy and its role in dynamic systems
  • Practice solving problems involving mass-spring systems and energy transformations
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Students studying physics, particularly those focusing on mechanics, as well as educators seeking to enhance their understanding of energy conservation in mass-spring systems.

Avery Woodbury
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1. A 1 kg block is on a flat frictionless surface. Attached to a relaxed spring (k=50N/m). A light string is attached to the block and runs over a frictionleas pulley to a .45kg dangling mass. If the dangling mass is released from rest, how far will if fall before stopping?

Homework Equations


U= 1/2kx^2
F=-kx
W=Fd
w=mg

(I'm not exactly sure which ones I do/don't need)[/B]

The Attempt at a Solution

:

I really have no idea where to begin. The answer the book gives is .176m. [/B]
 
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Write the energy conservation law for this system, and use the only energies that are present. So for gravity you would have a gravitational potential, and due to the spring there's also a spring energy, given by the U in your relevant equations section. Due to the nature of the conservation of energy, you may equate the two energies and notice how the distances of motion that both blocks trace are the same so you can use that two have only one variable for distance - x, and ultimately solve for it.
 

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