Conservation of energy of two blocks

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SUMMARY

The discussion focuses on the conservation of energy involving two blocks connected to a spring with a spring constant of 220 N/m. The blocks, with masses of 1.9 kg and 3.8 kg, are analyzed as one block falls a distance of 0.090 m. The combined kinetic energy of the two blocks at this distance is calculated to be 2.7 J, while the kinetic energy of the hanging block is determined to be 1.8 J. The maximum distance the hanging block falls before momentarily stopping is confirmed to be 0.39 m, illustrating the conversion of gravitational potential energy to spring potential energy.

PREREQUISITES
  • Understanding of gravitational potential energy (U = mgh)
  • Familiarity with spring potential energy (U = (1/2)kx^2)
  • Knowledge of kinetic energy calculations (K = (1/2)mv^2)
  • Basic principles of energy conservation in mechanical systems
NEXT STEPS
  • Study the principles of energy conservation in mechanical systems
  • Learn how to derive velocity from kinetic energy equations
  • Explore the relationship between potential energy and spring compression
  • Investigate advanced problems involving multiple masses and springs
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and energy conservation, as well as educators seeking to clarify concepts related to potential and kinetic energy in systems involving springs and blocks.

iamkristing
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[SOLVED] conservation of energy

Homework Statement


Two blocks, of masses M = 1.9 kg and 2M are connected to a spring of spring constant k = 220 N/m that has one end fixed, as shown in the figure below. The horizontal surface and the pulley are frictionless, and the pulley has negligible mass. The blocks are released from rest with the spring relaxed.

(a) What is the combined kinetic energy of the two blocks when the hanging block has fallen a distance of 0.090 m?
J

(b) What is the kinetic energy of the hanging block when it has fallen that 0.090 m?
J

(c) What maximum distance does the hanging block fall before momentarily stopping?
m
W0155-N.jpg



Homework Equations



k=(1/2)mv^2
u=mgh

ki + ui = kf + uf

The Attempt at a Solution



I solved A using u(grav) =kf +us and got 2.7 J
For B i got 1.8 J

C is where I have a problem. I know the kinetic energy must equal zero and somehow you find the height from u=mgh. I just can't seem to connect the two...
 
Last edited by a moderator:
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iamkristing said:
C is where I have a problem. I know the kinetic energy must equal zero and somehow you find the height from u=mgh. I just can't seem to connect the two...
The change in energy must be zero. You start with gravitational PE, which gets converted to spring PE.
 


iamkristing said:


Homework Equations



k=(1/2)mv^2
u=mgh

ki + ui = kf + uf

The Attempt at a Solution



I solved A using u(grav) =kf +us and got 2.7 J
For B i got 1.8 J

C is where I have a problem. I know the kinetic energy must equal zero and somehow you find the height from u=mgh. I just can't seem to connect the two...


For part A, when you say you used Ugrav = final kinetic energy + Spring potential energy, could you please elaborate as to how that was accomplished? If final kinetic energy is 0.5*mass*velocity, how did you calculate velocity?

For part B, I run into the same roadblock, the veocity.

For C, I don't understand how the distance is 0. The answer is supposed to be 0.39m (I'm referring to the answsers in the back.

I apologise for asking so much, but I would really like to understand how this problem is solved. Thank you in advance.

EDIT: Just realized that the thread is about a year old! I apologise for that...
 
Last edited:


iceman2048 said:
For part A, when you say you used Ugrav = final kinetic energy + Spring potential energy, could you please elaborate as to how that was accomplished? If final kinetic energy is 0.5*mass*velocity, how did you calculate velocity?

For part B, I run into the same roadblock, the veocity.
For both A and B you are solving for the final kinetic energy.

For C, I don't understand how the distance is 0. The answer is supposed to be 0.39m (I'm referring to the answsers in the back.
The distance is not zero. (That earlier post of mine states that the change in energy is zero, not the distance. That's just a statement of energy conservation.)
EDIT: Just realized that the thread is about a year old! I apologise for that...
Yeah, it generally doesn't make sense to respond to an old post... but here we are!
 

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