- #1

jacksonpeeble

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## Homework Statement

A 0.200-m uniform bar has a mass of 0.790 kg and is released from rest in the vertical position, as the drawing indicates. The spring is initially unstrained and has a spring constant of k = 20.0 N/m. Find the tangential speed with which end A strikes the horizontal surface.

## Homework Equations

E

_{up}=mgh=E

_{down}=.5Iw

^{2}+.5ky

^{2}

[tex]\sqrt{3(mgL-ky^{2}}[/tex]

## The Attempt at a Solution

[tex]\sqrt{.1^{2}+.2^{2}}-.1=.124[/tex]

[tex]\sqrt{\frac{3(.79 kg)(9.8 m/s/s)(.2 m)-(20 N/m)(.124 m)^{2}}{.790}}=2.343 m/s[/tex]

I think that I went about this the right way and simply made an arithmetic error or plugged in something incorrect. Any help will be greatly appreciated, as I must have this assignment completed by midnight.

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