Conservation of Linear Momentum problem

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SUMMARY

The discussion centers on a conservation of linear momentum problem involving two carts with masses of 2.3 kg and 1.5 kg, where the first cart is moving at +4.9 m/s and the second cart is at rest. The total momentum of the system is calculated using the formula p = m1v1 + m2v2, yielding a result of 7.5 kg*m/s. The velocity of the first cart when the second cart was at rest is determined to be 3.26 m/s. The initial confusion regarding the professor's provided answers of 2.15 kg*m/s and 0.935 m/s is clarified, confirming the student's calculations as correct.

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  • Understanding of linear momentum and its conservation principles
  • Familiarity with basic physics equations, specifically p = mv
  • Knowledge of mass and velocity units (kg and m/s)
  • Concept of frictionless motion in physics
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  • Review the principles of conservation of momentum in collisions
  • Explore examples of elastic and inelastic collisions
  • Learn about the effects of external forces on momentum
  • Study the implications of friction in real-world scenarios
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Students studying physics, particularly those focusing on mechanics and momentum, as well as educators seeking to clarify concepts related to momentum conservation in collisions.

mp9191
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1. Problem
A 2.3 kg cart is rolling across a frictionless, horizontal track towards a 1.5 kg cart that is initially held at rest. The carts are loaded with strong magnets that cause them to attract one another. Thus, the speed of each cart increases. At a certain instant before the carts collide, the first cart's velocity is +4.9 m/s and the second cart's velocity is -1.9 m/s.
a) What is the total momentum of the system of the two carts at this instant?
b) What was the velocity of the first cart when the second cart was still at rest?
2. Homework Equations :
p = m1v1 + m2v2
3. Solution:

a) p= 2.3*4.5 + 1.5*(-1.9) = 7.5 kg*m/s
b) 7.5 = 2.3v + 0
v= 7.5/2.3 = 3.26 m/s

Could someone please verify this solution? For some reason my prof gave me the answers
a) 2.15 kg*m/s
b) .935 m/s

which I'm pretty sure are incorrect... thanks in advance
 
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welcome to pf!

hi mp9191! welcome to pf! :wink:
mp9191 said:
A 2.3 kg cart is rolling across a frictionless, horizontal track towards a 1.5 kg cart that is initially held at rest. The carts are loaded with strong magnets that cause them to attract one another. Thus, the speed of each cart increases. At a certain instant before the carts collide, the first cart's velocity is +4.9 m/s and the second cart's velocity is -1.9 m/s.
a) What is the total momentum of the system of the two carts at this instant?
b) What was the velocity of the first cart when the second cart was still at rest?

a) p= 2.3*4.5 + 1.5*(-1.9) = 7.5 kg*m/s
b) 7.5 = 2.3v + 0
v= 7.5/2.3 = 3.26 m/s

Your answers look correct to me. :smile:

(except should that be 4.9 or 4.5 ??)
 
Oh, my bad. In part a) that should be 4.9 not 4.5.

Thank you! I thought I was going insane because I was like...there's no way it can be 2.15...
 

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