Conservation of mechanical energy of pendulum

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Homework Help Overview

The discussion revolves around the conservation of mechanical energy in the context of a pendulum bob swinging. The original poster questions the role of additional forces, specifically tension and air friction, in relation to the energy equation K + U = 1/2 mv² + mgh.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the identity of the additional force acting on the pendulum, with some suggesting tension and others considering air friction. Questions are raised about how these forces influence the conservation of mechanical energy and the energy equation.

Discussion Status

Participants are actively engaging with the question, providing insights into the nature of tension as a reaction force and its lack of contribution to potential energy. There is a recognition that tension redirects energy rather than contributing to it, although not all participants may fully agree on the implications.

Contextual Notes

There is an ongoing exploration of the assumptions regarding the forces acting on the pendulum, particularly in different motion scenarios, such as vertical versus horizontal movement.

mybrohshi5
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Homework Statement



Consider a pendulum bob swinging. The bob follows a circular path which indicates that gravity is not the only force acting upon it.

Identify the additional force; does it affect the equation K + U = 1/2 mv2 + mgh? why or why not?

The Attempt at a Solution



First i cannot figure out if the additional first it is talking about is the force of tension, or the force of friction on the bob by the air.

I want to say its tension but i can't figure out what to say about how tension would affect the equation or not.

If i say it is the friction force due to the air then i can say it doesn't affect the equation for a very long time because it would take the pendulum bob many oscillations before the force of friciton due to the air finally stopped the pendulum.

Any input on this would be very helpful.
Thank you :)
 
Last edited:
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This question is a bit weird. There are two forces on each simple pendulum: gravity and tension. If it moves in a vertical plane, or follows some other trajectory on the surface of a sphere of radius equal to its length, depends on the initial velocity and position vectors.

The pendulum can move along a horizontal circle if the resultant force is equal to the centripetal force needed for that orbit.

ehild
 
I think it was referring to the pendulum moving vertically.

So tension sounds like it is the other force the question is looking for.

Can you give any insight as to why tension affects or doesn't affect the conservation of mechanical energy?

Thanks for the help :)
 
mybrohshi5 said:
I think it was referring to the pendulum moving vertically.

So tension sounds like it is the other force the question is looking for.

Can you give any insight as to why tension affects or doesn't affect the conservation of mechanical energy?

Thanks for the help :)

The short answer is that it doesn't, as the tension force provides no additional kind of potential energy, U.

As for the longer answer, I may have rambled a bit, but here's my shot at it:

Well, forces like tension and the normal force are reaction forces. That means that they only act when there's something acting against them. If you let the object go, and don't let any other force act on it, nothing will happen. It will not gain any kinetic energy.

And that's what potential energy is all about. Potential energy measures how much work a conservative force (Such as a gravitational pull or electrical repulsion/attraction or a stretched/compressed spring) can do.

A tension or normal force cannot perform work on its own. It can only redirect the way energy goes. Whatever kinetic energy the pendulum bob gains comes at the expense of its gravitational potential energy, and not its "tension potential energy." And that's despite the fact that the tension force is the one making it oscillate horizontally.
 
Thank you RoyalCat. That was a great explanation :)

I appreciate it.
 

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