# Conservation of momentum and a uniform rod

## Homework Statement

The uniform rod (length 0.60 m, mass 1.0 kg) in Fig. 11-54 rotates in the plane of the figure about an axis through one end, with a rotational inertia of 0.12 kg·m2. As the rod swings through its lowest position, it collides with a 0.20 kg putty wad that sticks to the end of the rod. If the rod's angular speed just before collision is 2.4 rad/s, what is the angular speed of the rod–putty system immediately after collision?

http://edugen.wiley.com/edugen/courses/crs4957/halliday9118/halliday9118c11/image_n/nt0058-y.gif

IW=IW

I=mr^2

## The Attempt at a Solution

IW=IW
.12(2.4) = (.12 + mr^2) Wf
.12(2.4) = (.12 + .20(.60)Wf

## The Attempt at a Solution

Last edited:

i know .12 = 1/3ML^2

.12 is in the problem because its the inertia of the rod both before and after the collision

Sorry, it's been a while since I've done one of these problems.

Everything is correct, you just forgot to square the radius on the right hand side.

.12(2.4) = (.12 + .20(.60)Wf should be .12(2.4) = (.12 + .20(.60)^2)Wf