Conservation of Momentum in a Single Direction

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SUMMARY

The Law of Conservation of Momentum asserts that total linear momentum remains constant in a closed system devoid of external forces. This principle applies to individual directional components, confirming that momentum in the x-direction remains unchanged if no external forces act in that direction. The discussion emphasizes that momentum is a vector quantity, allowing for the analysis of momentum changes in specific directions independently. The example of a bowling pin and a ball illustrates how momentum conservation operates in two dimensions, reinforcing the vector nature of momentum.

PREREQUISITES
  • Understanding of vector quantities in physics
  • Familiarity with the concept of momentum
  • Basic knowledge of Newton's laws of motion
  • Ability to analyze two-dimensional motion
NEXT STEPS
  • Study the implications of Newton's Second Law in multi-directional systems
  • Explore vector decomposition techniques in physics
  • Learn about collisions and momentum transfer in two dimensions
  • Investigate real-world applications of momentum conservation in sports and engineering
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Students of physics, educators teaching mechanics, and anyone interested in understanding the principles of momentum conservation in both theoretical and practical contexts.

JSGandora
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The Law of Conservation of Momentum states that the total linear momentum does not change in any closed system not subject to external forces. However, is it true that the momentum in, say, the x-direction does not change in any closed system not subject to forces in the y-direction?

I feel that it is indeed true since y-directional forces do not change the x-directional velocity, thus conserving momentum in the x-direction.
 
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Hi JSGandora! :smile:
JSGandora said:
… is it true that the momentum in, say, the x-direction does not change in any closed system not subject to forces in the y-direction?

(you mean "not subject to forces in the x-direction")

Yes.

Conservation of momentum comes from the vector equation change of momentum = ∑ external forces.

Since this is a vector equation, you can take components in any direction, and if the component of ∑ external forces in that direction is 0, then the change of momentum in that direction is also 0. :wink:
 
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It does get a bit confusing. Think about a bowling pin at rest, and when you throw a ball at it (at a slight angle) the ball hits the pin, and they both fly off in the xy plane. So before the collision, the momentum in the x direction is whatever the mass of the ball is times the velocity. In the y direction, it's zero.
But after the collision, both objects move in the y direction…how does that work out? Well, consider the vector equations. The mass times the speed of the object moving "upwards" cancels out with the mass time sthe speed of the object moving "downwards".
Remember that momentum is a vector quantity since it's mass times Velocity.

P.S. are you from aops? :)
 
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