Conservation of momentum of astronaut in her space suit

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Homework Help Overview

The problem involves an astronaut in a space suit who loses her tether while on a spacewalk. She throws her oxygen tank to propel herself back towards her spacecraft. The discussion focuses on calculating the maximum distance she can be from the spacecraft while ensuring she can return within a specified time frame, as well as understanding the underlying physics principles, particularly Newton's laws of motion.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of the astronaut's final speed after throwing the oxygen tank and the implications for determining maximum distance. There are attempts to apply kinematic equations, with some questioning the appropriateness of using gravitational acceleration in a free space scenario. Others suggest considering the astronaut's acceleration and the forces acting on her.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem. Some have provided guidance on recalculating the astronaut's speed and considering the effects of negligible gravitational forces. There is recognition of errors in initial calculations, prompting further exploration of the astronaut's mass and the correct application of physics principles.

Contextual Notes

Participants note that the astronaut is in free space, which raises questions about the forces acting on her after throwing the oxygen tank. The lack of information regarding the mass of the spacecraft is also mentioned as a constraint in the calculations.

mandy9008
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Homework Statement


An astronaut in her space suit has a total mass of m1 = 91.3 kg, including suit and oxygen tank. Her tether line loses its attachment to her spacecraft while she's on a spacewalk. Initially at rest with respect to her spacecraft , she throws her oxygen tank of mass m2 = 12.0-kg away from her spacecraft with a speed v = 8.50 m/s to propel herself back toward it (see figure).
p6-25.gif


(a) Determine the maximum distance she can be from the craft and still return within 1.60 min (the amount of time the air in her helmet remains breathable).
(b) Explain in terms of Newton's laws of motion why this strategy works.


Homework Equations


m1v1i + m2v2i = m1v1f + m2v2f


The Attempt at a Solution


a. (91.3 kg)(0 m/s) + (12.0 kg)(0 m/s) = (91.3 kg)v1f + (12.0 kg)(8.50 m/s)
v1f=1.112 m/s
b. When the astronaut throws her oxygen tank, she applies a force onto it. At the same time, the oxygen tank is applying a force onto her, which pushes the astronaut towards the space ship. This is an example of Newton's Third Law.
 
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You calculate the speed correctly in part (a), but that's not what the problem is asking for. You need to find a maximum distance.

Part (b) is OK.
 
okay, so I need to solve for change in x, right?
x=vt + 1/2 gt^2
x= (1.118 m/s)(96 s) + 1/2 (9.8 m/s^2)(96s)^2
x=45265.7 m

that does not seem right at all
 
mandy9008 said:
okay, so I need to solve for change in x, right?
x=vt + 1/2 gt^2
x= (1.118 m/s)(96 s) + 1/2 (9.8 m/s^2)(96s)^2
x=45265.7 m

that does not seem right at all

I think you need to consider projectile motion concept.
 
mandy9008 said:
okay, so I need to solve for change in x, right?
x=vt + 1/2 gt^2
x= (1.118 m/s)(96 s) + 1/2 (9.8 m/s^2)(96s)^2
x=45265.7 m

that does not seem right at all

The astronaut is in free space, not on the surface of Earth! Is there any force acting on she after she has thrown the oxygen tank away? This is not a projectile motion.


ehild
 
okay so, do i need to find her acceleration and use that in place of g?
 
mandy9008 said:
okay so, do i need to find her acceleration and use that in place of g?

You know that acceleration is force over mass. What can exert force on the astronaut in free space?

ehild
 
I don't know. I know that it is not gravitational, since you said that I can't use 9.8 m/s^2
 
Is gravitational acceleration 9.8 m/s^2 everywhere in the world? On the surface of the Moon for example? Have you seen films about astronauts walking on the Moon?

There is gravitational interaction between any objects with mass. Do you know the formula?

ehild
 
  • #10
mandy9008 said:
okay, so I need to solve for change in x, right?
x=vt + 1/2 gt^2
x= (1.118 m/s)(96 s) + 1/2 (9.8 m/s^2)(96s)^2
x=45265.7 m

that does not seem right at all
Repeat the calculation using the same equation with zero acceleration and you are done. Although there is gravitational attraction between the spacecraft and the astronaut, it should be considered negligible. Besides, the mass of the spacecraft is not given so you cannot calculate it.
 
  • #11
x= (1.118 m/s)(96 s) + 1/2 (0 m/s^2)(96 s)^2
x=107.328m
this is not correct.
 
  • #12
mandy9008 said:

The Attempt at a Solution


a. (91.3 kg)(0 m/s) + (12.0 kg)(0 m/s) = (91.3 kg)v1f + (12.0 kg)(8.50 m/s)
v1f=1.112 m/s
You made an error here. 91.3 kg is her total mass including suit and oxygen tank. If her oxygen tank is 12 kg, what's the mass of her and her suit?

Redo this to get the correct speed after she throws the tank.
 
  • #13
okay that makes sense. x=123.5 m Thank You
 

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