Conservation of Linear Momentum Problem

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SUMMARY

The discussion centers on a conservation of linear momentum problem involving two identical twins, each with a mass of 52.6 kg, and a backpack weighing 12.0 kg. Twin A throws the backpack horizontally at a speed of 3.40 m/s to Twin B while both are initially at rest on a frictionless surface. The conservation of linear momentum equation, m1v1i + m2v2i = m1v1f + m2v2f, is applied twice: first when the backpack is thrown and then again when it is caught, allowing for the calculation of the subsequent speeds of both twins.

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MG5
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Identical twins, each with mass 52.6 kg, are on ice skates and at rest on a frozen lake, which may be taken as frictionless. Twin A is carrying a backpack of mass 12.0 kg. She throws it horizontally at 3.40 m/s to Twin B. Neglecting any gravity effects, what are the subsequent speeds of Twin A and Twin B?

I think I'd use conservation of linear momentum wouldn't I?

m1v1i + m2v2i = m1v1f + m2v2f

Would I do it twice? Once for when the backpack is thrown and then again for when it is caught?
 
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Hi MG5! :smile:
MG5 said:
I think I'd use conservation of linear momentum wouldn't I?

m1v1i + m2v2i = m1v1f + m2v2f

Would I do it twice? Once for when the backpack is thrown and then again for when it is caught?

Yes! :smile: And yes! :smile: And yes! :smile:
 

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