Conservation of Momentum of two carts Problem

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SUMMARY

The discussion centers on the conservation of momentum involving two carts, each with a mass of 1 kg. The first cart moves right at 4 m/s, while the second cart moves left at 2 m/s. The total momentum vector is calculated as [2, 0, 0] kg·m/s after the collision, where the first cart comes to rest. The final velocity of the second cart is determined to be [2, 0, 0] m/s in column vector notation.

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Homework Statement



Two carts, each with a mass of 1kg, are moving along a track towards one another. One cart is moving to the right at 4m/s and the other is moving to the left at 2m/s. Write down the momentum vector for each cart in column vector notation. Add these together to get the total momentum vector for the system of carts. Assuming this is conserved in the impending collision, and that the cart initially moving to the right ends up at rest after the collision, find the final velocity of the second cart in column vector notation.

Homework Equations




The Attempt at a Solution



ma = 1kg
vaix = 4m/s
vafx = 0 m/s

mb = 1kg
vbix = -2m/s
vbfx = ?

ma*vai + mb*vbix = ma*vafx + mb*vbfx

(1 kg)([4,0,0]m/s) + (1kg)([-2,0,0]m/s) = (1kg)([0,0,0]m/s) + (1kg)(vbfx)

vbfx = [2,0,0] m/s (is this correct column vector notation?)
 
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That's a row-vector, actually. Column vectors are either witten as the transpose of a row-vector
[2,0,0]T, which is convenient if you want it to fit in a line. Or it can also written as

[tex]\left[\begin{array}{cc}2\\0\\0\end{array}\right][/tex]
 

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