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Conservation of momentum question

  1. Oct 24, 2011 #1
    Ok, I've been wondering about this question for many years and I don't know whether I just don't understand the basic concepts enough.

    If you have a rapidly-spinning neutron star that continues to collapse down to a singularity, what happens to the conservation of angular momentum from the spin? As the circumference of the neutron star approaches zero, what happens to the speed of the spin? Would it actually have to approach c? Would the energy get bled off into some other form?
     
  2. jcsd
  3. Oct 24, 2011 #2
    When I clicked on this link I thought that there might be a 1kg mass in a completely elastic collision with something :wink:. Cool question though, sorry I don't know squat about this kinda stuff.
     
  4. Oct 24, 2011 #3

    DaveC426913

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    Well, neutron stars do not collapse to a singularity; they typically are about 20km in diameter, with masses on the order of the sun.

    Read about rotation here:
    http://en.wikipedia.org/wiki/Neutron_star#Rotation

    It suggests newborn (i.e. fastest) neutron stars rotate on the order of once per second, which with a circumference of a mere 64km, is quite slow.
     
    Last edited: Oct 24, 2011
  5. Oct 24, 2011 #4
    Thanks. Not sure if I've posted this in the right section, though.
     
  6. Oct 24, 2011 #5
    Ok, then if a star is collapsing down past neutron star stage and it was spinning, does that apply?
     
  7. Oct 24, 2011 #6
    You definitely did, I didn't even read the category
     
  8. Oct 24, 2011 #7

    PAllen

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    A black hole can have angular momentum and charge. In fact, externally, once stabilized, a black hole is fully characterized by mass, charge, and angular momentum.
     
  9. Oct 24, 2011 #8
    Cool. So, as the circumference of the black hole shrinks, the rate of spin increases, correct? If the circumference approaches zero, what happens to the rate of spin? Would this have any effect on a practical limit to how small a black hole could become?
     
  10. Oct 24, 2011 #9

    PAllen

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    Externally you get event horizon(s). Inside the event horizon you get a ring singularity. A point singularity only occurs for a non-rotating black hole. In GR, spacetime curvature (the metric) can incorporate angular momentum, so the complete black hole structure can be said to have angular momentum. Inside the horizon, nobody believes the idealized Kerr black hole describes what would really happen. This is outside currently understood physics (IMO).
     
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