Al and Bert are jogging side by side on a trail in the woods at a speed of 0.75 m/s. Suddenly, Al sees the end of the trail 35 m ahead and decides to speed up to reach it. He accelerates at constant rate of 50 m/(s^2) while Bert continues on at a constant speed. (a) How long does it take Al to reach the end of the hill?
Part (a) is the one I'm having trouble understanding.
Δx = (1/2)at^2 + Vt + X
The Attempt at a Solution
35 = (1/2)(0.50)t^2 + (0.75)t
35 = (0.25)t^2 + (0.75)t
35 = t[(0.25)t + 0.75]
35/t = (0.25)t + 0.75
And, that is where I stopped. I'm sure I pretty much went wrong at the third step.