Constant horizontal force and friction

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SUMMARY

The discussion centers on a physics problem involving a 50 kg object pushed across a floor by a constant horizontal force of 200 N. The force of friction is determined to be equal to the applied force, resulting in a friction force of 200 N. This conclusion is based on the assumption that the object moves at a constant velocity, which implies that the net force acting on the object is zero. The coefficient of friction can be calculated if the assumption of constant velocity is accepted, despite the problem's lack of explicit information regarding this condition.

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  • Understanding of Newton's laws of motion
  • Familiarity with the concept of friction and its coefficients
  • Knowledge of force diagrams and free-body diagrams
  • Basic algebra for solving equations
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rasen58
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Homework Statement


A 50 kg is pushed across a floor by a constant horizontal force of 200 N. What is the force of friction?

Homework Equations


Ffr = coeff*Fn

The Attempt at a Solution


I'm not sure how to find it as I don't know the coefficient.
The answer says the answer is 200 N, but I don't know why it's equal to the applied force. The problem didn't say it was being moved at a constant velocity, it only has a constant applied force.
 
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Check the problem statement for any other information. You feel it's incomplete as it stands, and it is incomplete as it stands.
 
Bystander said:
Check the problem statement for any other information. You feel it's incomplete as it stands, and it is incomplete as it stands.

Is the problem written correctly and completely or is there some missing parts !??
 
That's all that was given. I guess whoever wrote the problem wrote it incompletely.
 
Solve it for the coefficient of friction necessary for constant velocity, and include an explanation that you're making an assumption based on the given answer.
 

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