Constructing a Continuous Function with 2 Different Range Values

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A continuous function cannot have a range consisting of only two distinct values without exhibiting jumps, contradicting the intermediate value theorem. Despite this, a professor asserts that such a function can exist, suggesting a deeper understanding of continuity is necessary. Peer opinions and external sources, including Dr. Math, support the view that it's impossible under standard conditions. The discussion highlights confusion regarding the definitions of continuity and the implications of topology. Ultimately, the consensus leans towards the impossibility of constructing such a function.
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Homework Statement


Provide an example of f:D-->R which is continuous but whose range has two different numbers only.


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The Attempt at a Solution


For the range to have only two different values, it's seems impossible to construct a continuous function without jumps. In fact, it seems like the intermediate value theorem could prove this.

I've asked my professor if this is possible, he says it is, and that studying the definitions of continuous closely will reveal it.

Then I've asked a few friends, who are very good at math, and they say it isn't. I also asked Dr. Math, and got a response from Dr. Tom, who says it isn't.
 
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In the usual topology, any function from a discrete set is continuous.
 
snipez90 said:
In the usual topology, any function from a discrete set is continuous.

Thanks

I feel like a moron.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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