Continuous Function and Integral Proof

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SUMMARY

The discussion focuses on proving the continuity of a function f defined on an interval [a, b] under the condition that the absolute difference between f(u) and f(v) is bounded by the absolute difference between u and v. The proof establishes that f is continuous at every point in [a, b]. Additionally, it demonstrates that if f is integrable on [a, b], then the integral of f over this interval approximates the value (b - a)f(c) within a specific bound, specifically | ∫ab f(x)dx - (b - a)f(c) | ≤ (b-a)²/2 for any c in [a, b].

PREREQUISITES
  • Understanding of continuity in real analysis
  • Familiarity with the properties of integrable functions
  • Knowledge of the Mean Value Theorem for integrals
  • Basic proficiency in limit definitions and epsilon-delta proofs
NEXT STEPS
  • Study the epsilon-delta definition of continuity in detail
  • Explore the properties of integrable functions in real analysis
  • Learn about the Mean Value Theorem for integrals and its applications
  • Review proofs related to the convergence of integrals and their approximations
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Students and educators in mathematics, particularly those studying real analysis, calculus, or preparing for advanced topics in mathematical proofs and integrals.

AndersCarlos
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Homework Statement



Let f be a function such that:

[tex]\left |f(u) - f(v) \right | \leq \left | u - v\right |[/tex]

for all 'u' and 'v' in an interval [a, b].

a) Prove that f is continuous at each point of [a, b]
b) Assume that f is integrable on [a, b]. Prove that:
[tex]\left | \int_{a}^{b} f(x)dx - (b - a)f(c)\right | \leq \frac{(b-a)^{2}}{2}[/tex]

for any 'c' in [a, b].

Homework Equations



a)

I considered that:

[tex]\left | f(u) - f(v) \right | < \epsilon[/tex]
[tex]\left | u - v \right | < \delta[/tex]

b)

I rewrote [tex](b - a)f(c)[/tex] as:

[tex]\int_{a}^{b} f(c)dx[/tex]

The Attempt at a Solution



a) I've attempted to consider [tex]\delta \geq \epsilon[/tex] Since the absolute value of the difference between 'u' and 'v' will be greater or equal to the absolute value of the difference between the difference of 'f(u)' and 'f(v)'. But no conclusive proof without supposing was achieved.

b) Maybe considering [tex]g(x) = \int_{a}^{b} f(x)dx[/tex] So as the integral can be considered as a function, I could use relation: [tex]\left |f(u) - f(v) \right | \leq \left | u - v\right |[/tex]
 
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Just a little information: This is question 33, section 3.6, chapter 3 from Apostol Vol. 1. I would really appreciate any help. I know that maybe no one will answer, but thanks anyway.
 

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