Hi !(adsbygoogle = window.adsbygoogle || []).push({});

My name is Max and I'm a Mechanical Engineer.

I'm working on Control Moment Gyroscope project, but because for a long time I didn't deal with theory, I'm stuck at some very basic dynamics problem.

In this article

http://www.spacecraftresearch.com/files/BrownPeck_JGCD2009

the author writes that the total CMG torque is

[itex]{\tau _{cmg}} = \dot \phi \hat g \times {h_r}[/itex] (eq. 8)

and the gimbal motor torque is

[itex]{\tau _g} = {I_{cmg}}\ddot \phi + {I_{cmg}}{\mathop \omega \limits^B ^{B/N}} \cdot \hat g + ({\omega ^{B/N}} \times {h_r}) \cdot \hat g[/itex] (eq. 9)

But what happens practically if I mount the CMG at the top of a static table at my room, connect both motors (flywheel and gimbal) to power and wait for some steady state ?

In the first equation we get some constant torque that CMG applies to the table, because [itex]\dot \phi [/itex] is some constant value, but on the other side, the gimbal motor torque, [itex]{\tau _g}[/itex] has to be zero, because there is no angular acceleration: [itex]\ddot \phi = 0

[/itex], and the table is static, that is, [itex]{\mathop \omega \limits^B ^{B/N}} = 0[/itex] and [itex]{\mathop \omega \limits^{B/N}} = 0[/itex]. That is, we need torque only to accelerate the gimbal.

My question is how the CMG can to apply torque to the controlled body (table, satellite etc), actually without torque at a gimbal motor ?

Many thanks in advance,

Max

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# Control Moment Gyroscope Gimbal Motor Torque

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