christoff
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Homework Statement
Consider the function [tex]f_n(x)=n\cdot I\left[|x|<\frac{1}{2n}\right][/tex] considered as a distribution in [itex]D'(\mathbb{R})[/itex], where [itex]I[/itex] denotes the indicator function. Recall that [itex]f_n[/itex] converges to [itex]\delta_0[/itex], the delta distribution, in [itex]D'(\mathbb{R})[/itex]. Show that [itex]f_n^2-n\delta_0[/itex] converges in [itex]D'(\mathbb{R})[/itex].
The Attempt at a Solution
By a few calculations, we can show that for any test function [itex]\phi[/itex] and natural [itex]n>0[/itex], that
[tex](f_n^2,\phi)=n(f_n-\delta_0,\phi).[/tex]
At this point, I would be tempted to say that this converges to zero (as a sequence of real numbers) because [itex](f_n-\delta_0,\phi)[/itex] "must" dominate the convergence of [itex]n[/itex] to infinity. However, this isn't rigorous, and is more of a hunch than anything. However, any attempts I've made to prove it have not gone anywhere. I feel as though it must have something to do with the smoothness of the test functions, but I can't see where to incorporate this.
At this point, I would appreciate a nudge in the right direction.
Thanks in advance!