Convergence of \sum \frac{r^k}{k^r} for Positive Numbers r

  • Thread starter Thread starter zeion
  • Start date Start date
  • Tags Tags
    Numbers
Click For Summary

Homework Help Overview

The discussion revolves around determining the positive numbers \( r \) for which the series \( \sum \frac{r^k}{k^r} \) converges. Participants are exploring the convergence criteria using the ratio test.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to apply the ratio test by analyzing the limit of the ratio of successive terms in the series. There are questions about the equality of expressions and the implications of the limit approaching certain values.

Discussion Status

The discussion is active with participants questioning the conditions for convergence and the behavior of the ratio as \( k \) approaches infinity. Some guidance has been offered regarding the positivity of \( r \) and its implications for convergence, but there is no explicit consensus on the final values of \( r \) that ensure convergence.

Contextual Notes

Participants are working under the assumption that \( r \) must be a positive number, and there is some confusion regarding the application of the ratio test and the conditions for convergence.

zeion
Messages
455
Reaction score
1

Homework Statement



Find the positive numbers r for which [tex]\sum \frac{r^k}{k^r}[/tex] converges.

Homework Equations





The Attempt at a Solution



What method do I use for this?

[tex]\frac {a_{k+1}}{a_k} = \frac {r^{k+1}}{(k+1)^r} \cdot \frac{k^r}{r^k}<br /> = r \cdot (\frac{1}{k})^{\frac{r}{k}}[/tex]
 
Physics news on Phys.org
zeion said:

Homework Statement



Find the positive numbers r for which [tex]\sum \frac{r^k}{k^r}[/tex] converges.

Homework Equations





The Attempt at a Solution



What method do I use for this?

[tex]\frac {a_{k+1}}{a_k} = \frac {r^{k+1}}{(k+1)^r} \cdot \frac{k^r}{r^k}<br /> = r \cdot (\frac{1}{k})^{\frac{r}{k}}[/tex]
The second and third expressions aren't equal...
 
Ok so I have [tex]\frac {a_{k+1}}{a_k} = \frac {r^{k+1}}{(k+1)^r} \cdot \frac{k^r}{r^k}<br /> = r \cdot \frac{k^r}{(k+1)^r } = r \cdot (\frac{k}{(k+1)})^r[/tex] ?
 
then [tex]r \cdot (1 - \frac{1}{k+1})^r \to r \cdot 1^r[/tex] ?
 
then r needs to be < 1?
 
What if r = -200? That's less than 1.
 
I thought if the ratio is < 1 then it converges?
 
The ratio test is usually given in terms of absolute values. IOW,
[tex]\lim_n \frac{|a_{n + 1}|}{|a_n|}[/tex]

For this problem it's given that r is a positive number, so since the ratio of those terms is less than 1, the series converges.
 
So how do I know the ratio is less than 1?
 
  • #10
I thought you already knew that. What I thought you did was to evaluate this limit:
[tex]\lim_{k \to \infty} \frac {a_{k+1}}{a_k} = \lim_{k \to \infty} \frac {r^{k+1}}{(k+1)^r} \cdot \frac{k^r}{r^k}= \lim_{k \to \infty} r \cdot \frac{k^r}{(k+1)^r } = \lim_{k \to \infty} r \cdot (\frac{k}{(k+1)})^r[/tex]
What do you get for this limit? And what does that value imply for the test you are using?
 
  • #11
I get [tex]r \cdot 1^r = r[/tex]?
And r is positive
 
  • #12
zeion said:
Find the positive numbers r for which [tex]\sum \frac{r^k}{k^r}[/tex]
converges.
From your work, what are the values of r that cause this series to converge?
 
  • #13
I need the ratio to approach something < 1?
So since r is positive I need it to be 0 < r < 1?
 
  • #14
C'mon, show some confidence. Tell me, don't ask me.
 
  • #15
zeion said:
I need the ratio to approach something < 1?
So since r is positive I need it to be 0 < r < 1?
C'mon, show a little confidence in your ability. Tell me, don't ask me.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 22 ·
Replies
22
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
1
Views
967
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K