Convergence of \sum_{n=0}^{\infty} zeta^{(n)}(s)

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Homework Statement



Does the sum [tex]\sum_{n=0}^{\infty} zeta^{(n)}(s)[/tex] converge regardless of s, where n is the nth derivative of the Riemann Zeta function? If it converges tell what value it converges to.

Homework Equations





The Attempt at a Solution



I used the integral test, and I think it diverges. Plus, by plotting the sequence on Matematica, it looks like it is diverging. Am I correct?
 
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Divergent, but you can still resum the series using Borel resummation.
 


Can anyone prove that the sum [tex]\sum_{n=0}^{\infty} zeta^{(n)}(s)[/tex] goes to INFINITY not just diverges
 


seanhbailey said:
Can anyone prove that the sum [tex]\sum_{n=0}^{\infty} zeta^{(n)}(s)[/tex] goes to INFINITY not just diverges

Apply the operator 1 - d/ds to the summation. To investigate convergence, you can apply it to the partial sums of the first n terms. If you apply it formally to the infinite summation then you get the same result you would get after performing the Borel resummation.