Convergence of x_n: Limit in Complex Field

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SUMMARY

The sequence defined by x_n=n(e^{\frac{2\pi i}{n}}-1) converges in the complex field. The limit is established as |x_n|=2\pi i as n approaches infinity. To demonstrate this convergence, one should utilize the power series expansion of the exponential function. This approach provides a clear pathway to derive the limit effectively.

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BSCowboy
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Could someone please provide me a little direction.
I'm trying to show this sequence converges

x_n=n\left(e^{\frac{2\pi i}{n}}-1\right)

I know \lim_{n\rightarrow\infty}|x_n|=2\pi i, but I have no idea how to arrive at the solution.

This is not a homework question.
 
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The obvious thing to do would be to expand the exponential term as a power series.
 

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