Converging Series Homework: Can't Prove It!

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    Converging Series
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Homework Help Overview

The discussion revolves around the convergence of three infinite series involving trigonometric and logarithmic functions. The original poster expresses uncertainty about how to approach proving the convergence of these series.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of the comparison test for determining convergence, with some suggesting manipulations of the series terms to facilitate comparison.

Discussion Status

Some participants have provided guidance on how to apply the comparison test, prompting further exploration of the remaining series. There is an ongoing examination of the reasoning behind the original poster's initial answers and the conditions under which the series may converge.

Contextual Notes

The original poster has indicated a lack of proof for their answers and is seeking clarification on the application of the comparison test. There is a noted uncertainty regarding the convergence of the third series.

Mattofix
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Homework Statement



I have done really well previous to these questions but i don't have a clue where to start any of them.

Do these converge?

i) Sum from n=1 to infinty of sin(2^n)/2^n

ii) Sum from n=1 to infinty of ncosn/(n^3 + logn)

iii) Sum from n=1 to infinty of (logn)^4/n^2


Homework Equations



Use comparison test but i can't get it them in a simple form or definitely prove it.



The Attempt at a Solution



i) yes

ii)yes

iii)unsure

No proof though...hmmmm...
 
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You must have some reason for the yes answer on i) and ii). What is it? Remember in the comparison test you can do anything to the numerator that makes it larger and anything to the denominator that makes it smaller (in absolute value). If the resulting series converges, so does the original series. Now what's a nice round number that is greater than sin(2^n)?
 
beutiful man - got that one - how about the other 2?
 
Same trick n/n^3>cos(n)*n/(n^3+log(n)). The third is a little trickier. Do you know that log(n)/n^p goes to zero as n->infinity for all p>0?
 

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