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copitlory8
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Homework Statement
A roller coaster (365. kg) moves from A (5.00 m above the ground) to B (28.0 m above the ground). Two nonconservative forces are present: friction does -2.00 multiplied by 104 J of work on the car, and a chain mechanism does +3.00 multiplied by 104 J of work to help the car up a long climb. What is the change in the car's kinetic energy, ΔKE = KEf - KE0, from A to B?
Homework Equations
change in kinetic energy =work or final KE minus initial KE.
Work=force x distance
change in KE= .5(m)(final velocity)^2
The Attempt at a Solution
I used the constant acceleraton euqation to solve for final velocoty. And the formula .5(m)(final velocity)^2 to calculate KE.
I got 10000. This answer was wrong.