(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A roller coaster (365. kg) moves from A (5.00 m above the ground) to B (28.0 m above the ground). Two nonconservative forces are present: friction does -2.00 multiplied by 104 J of work on the car, and a chain mechanism does +3.00 multiplied by 104 J of work to help the car up a long climb. What is the change in the car's kinetic energy, ΔKE = KEf - KE0, from A to B?

2. Relevant equations

change in kinetic energy =work or final KE minus initial KE.

Work=force x distance

change in KE= .5(m)(final velocity)^2

3. The attempt at a solution

I used the constant acceleraton euqation to solve for final velocoty. And the formula .5(m)(final velocity)^2 to calculate KE.

I got 10000. This answer was wrong.

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# Homework Help: COnversative Forces and Change in Kinetic Energy

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