1. The problem statement, all variables and given/known data A roller coaster (365. kg) moves from A (5.00 m above the ground) to B (28.0 m above the ground). Two nonconservative forces are present: friction does -2.00 multiplied by 104 J of work on the car, and a chain mechanism does +3.00 multiplied by 104 J of work to help the car up a long climb. What is the change in the car's kinetic energy, ΔKE = KEf - KE0, from A to B? 2. Relevant equations change in kinetic energy =work or final KE minus initial KE. Work=force x distance change in KE= .5(m)(final velocity)^2 3. The attempt at a solution I used the constant acceleraton euqation to solve for final velocoty. And the formula .5(m)(final velocity)^2 to calculate KE. I got 10000. This answer was wrong.