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Convert a region into a rectangle

  1. Mar 23, 2013 #1
    1. The problem statement, all variables and given/known data

    Let R be the region bounded by x^3/2+y^3/2=a^3/2 (x>0, y>0) and the coordinate axes x=0, y=0. Express it in double integral over a rectangle.

    2. Relevant equations



    3. The attempt at a solution

    How to solve this people please?

    I tried a couples time but failed to find v u which is essential to solving this problem as all we have to do is find ∂(u,v)/∂(x,y)

    cheers
     
    Last edited by a moderator: Mar 24, 2013
  2. jcsd
  3. Mar 24, 2013 #2

    SammyS

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    What specifically have you tried?
     
  4. Mar 24, 2013 #3
    let u=y/(a^1.5-x^1.5)^2/3 and v=x/(a^1.5-y^1.5)^2/3
    got 0 for this
    let u=y/(a^1.5-x^1.5)^2/3 and v=x/y this got really nasty
    so i just dunno the trick of findin proper v and u
     
  5. Mar 24, 2013 #4

    SammyS

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    Try [itex]\displaystyle u=x^{3/2}+y^{3/2} \,,\ [/itex] and [itex]\displaystyle v=x^{3/2}-y^{3/2} \,,\ [/itex]

    You may have to do some tweaking on this.
     
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