# Convert the polar equation to rectangular form.

1. Jan 5, 2014

### Lebombo

1. The problem statement, all variables and given/known data

r = 3sin$\theta$

since

x= rcos$\theta$

x = 3sin$\theta$cos$\theta$

and since:

y = rsin$\theta$

y = 3$sin^2\theta$

Then I'm sort of stuck..

2. Jan 5, 2014

### LCKurtz

You are making it way too difficult. Put $\sin\theta =\frac y r$ in your first equation then see if you can get an xy equation from that.

3. Jan 5, 2014

### Dick

Try putting sinθ=y/r.

4. Jan 6, 2014

### Lebombo

Like so:

r = 3sinθ becomes (r=3$\frac{y}{r}$)

= (r =$\sqrt{3y}$) ?

or solving for y, (y = $\frac{r^2}{3}$)

or do you mean something like this:

($\frac{y}{r} = sinθ$) becomes ($\frac{y}{3sinθ} = sinθ$)

= (y = 3sin$^{2}θ$)

5. Jan 6, 2014

### Dick

You also want to use $r^2=x^2+y^2$. You need to express both $sin(\theta)$ and r in terms of x and y. Try once more.

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