Convert the polar equation to the Cartesian equation

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SUMMARY

The discussion focuses on converting the polar equation \( r^2 = 26r \cos \theta - 6r \sin \theta - 9 \) into its Cartesian equivalent. The correct transformation results in the equation \( (x - 13)^2 + (y + 3)^2 = 169 \), confirming option (d) as the accurate answer. Key equations utilized include \( x = r \cos \theta \), \( y = r \sin \theta \), and \( x^2 + y^2 = r^2 \). The solution process involves algebraic manipulation to achieve the final Cartesian form.

PREREQUISITES
  • Understanding of polar coordinates and their relationship to Cartesian coordinates
  • Familiarity with algebraic manipulation and completing the square
  • Knowledge of trigonometric identities and their applications in coordinate transformations
  • Proficiency in solving quadratic equations
NEXT STEPS
  • Study the conversion methods between polar and Cartesian coordinates
  • Learn about the geometric interpretations of polar equations
  • Explore the implications of completing the square in quadratic equations
  • Investigate the applications of polar coordinates in advanced mathematics and physics
USEFUL FOR

Students studying mathematics, particularly those focusing on coordinate geometry, algebra, and trigonometry. This discussion is beneficial for anyone needing to understand the conversion between polar and Cartesian equations.

Fatima Hasan
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Homework Statement


Replace the polar equation with an equivalent Cartesian equation.

##r^2 = 26r cos θ - 6r sin θ - 9##
a)##(x - 13)^2 + (y + 3)^2 = 9##
b)##(x + 26)^2 + (y - 6)^2 = 9##
c)##26x - 6y = 9##
d)##(x - 13)^2 + (y + 3)^2 = 169##

Homework Equations


##x= r cos \theta##
##y= r sin \theta##
##x^2+y^2 = r^2##

The Attempt at a Solution


##r^2 = 26r cos θ - 6r sin θ - 9##
##x^2 + y^2 = 26 x - 6 y -9 ##
##x^2 -26x + y^2 + 6 y = -9 ##
##(x-13)^2 - 169 + ( y+3 )^2 -9 = -9##
##(x-13)^2 + (y+3)^2 = 169 ##
The answer is (d) . Right ?
 
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