Convert voltage to acceleration

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Discussion Overview

The discussion revolves around the conversion of voltage output from an accelerometer to acceleration, focusing on the relationship between voltage, sensitivity, and the resulting acceleration units. Participants explore the mathematical relationships and unit conversions involved in this process.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • Some participants inquire about the method to convert voltage to acceleration using the accelerometer's sensitivity, specifically noting an output voltage of 2.5 V and a sensitivity of 9.9 mV/g.
  • One participant suggests examining the units involved in the conversion, questioning whether to multiply or divide to achieve the desired units.
  • Another participant proposes that dividing voltage by the sensitivity (in mV/g) yields acceleration in g.
  • A further response confirms the division approach, emphasizing that units behave like ordinary fractions in calculations.
  • There is a request for book sources to validate the conversion method discussed, with references to instrumentation and algebra texts.
  • One participant provides a link to a resource on dimensions and units, suggesting it may be helpful.

Areas of Agreement / Disagreement

Participants generally agree on the method of dividing voltage by sensitivity to obtain acceleration, but there is no consensus on the need for external sources to validate this approach.

Contextual Notes

Some participants express uncertainty regarding the need for proof from textbooks, indicating a reliance on algebraic principles for unit conversion without resolving the specific sources required.

manutdkaki
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May i know how to convert voltage to acceleration from accelerometer ?

output voltage = 2.5 v and sensitivity of accelerometer is 9.9mv/g
 
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manutdkaki said:
May i know how to convert voltage to acceleration from accelerometer ?

output voltage = 2.5 v and sensitivity of accelerometer is 9.9mv/g

Look at the units you're starting with and what the units are for the conversion constant ("sensitivity"). Do you want to multiply or divide to get the units you're looking for?
 
can voltage divide sensitivity of accelerometer to get acceleration result ?

v / mv/g = g
 
hi manutdkaki :smile:
manutdkaki said:
v / mv/g = g

that's right …

the beauty of units is that they multiply and divide exactly like ordinary fractions :smile:

v / (mv/g) = vg/mv = g/m = kg :wink:
 
v/(mv/g)

v is voltage
mv = milivoltage
g= acceleration

got any book source to prove it ?
thanks
 
i hope can get from instrumentation book to prove it . thanks tiny-tim
 
manutdkaki said:
got any book source to prove it ?

manutdkaki said:
i hope can get from instrumentation book to prove it .

Units are treated as variables. So you can prove it with elementary algebra. I guess you need a book on algebra.
 

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