Sketching output waveforms while considering slew rate

  • #1
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Homework Statement:

Sketch the output voltage when input voltage applied to non inverting amplifier with gain 10 for a square wave input signal with peak to peak voltage ##2 V##, ##50 %## duty cycle and frequency ##1## kHz. Supply Voltage is +12 V and -12V, the op amp has slew rate 0.5 V/ microsecond and the op amp is nulled initially.

Relevant Equations:

Time Period = 1 / Frequency

Duty Cycle = (Pulse Width *100)/ Time Period
1. Using the frequency equation I know the time period is 1 millisecond.

2. The duty cycle (50%) equation tells me that the pulse width and the amplitude is 1 V.

3. Thus the input waveform looks like this : (?)

IMG_20200601_170230027_2.jpg


4. As the slew rate is 0.5 volts per microsecond, the output voltage would take 4 microseconds to go from -1 V to + 1V (?)

5. Thus the output waveform for one pulse should look like :

IMG_20200601_170746425_2.jpg


(I converted milliseconds to microseconds)

Is this correct?
 

Answers and Replies

  • #2
cnh1995
Homework Helper
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5. Thus the output waveform for one pulse should look like :
You have not considered the gain.
 
  • #3
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You have not considered the gain.
Oof! Careless of me. Other than that bit is the rest fine?
 
  • #4
berkeman
Mentor
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Oof! Careless of me. Other than that bit is the rest fine?
The horizontal axis is not to scale, even ignoring the voltage gain issue. The rise/fall times are on the order of a few us, while the period of the square wave input is on the order of a ms. Do you have any ideas for how to represent that on a plot? How would you observe this on a digital oscilloscope, for example?
 
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