Converting 27.84×10⁻⁶ to 3.593×10⁴ in integration problem

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PCal
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1. The problem statement, all given data
I've been working through one of the lessons for my HNC and I'm totally stuck on how they got from 27.84x10^-6 to 3.593x10^4. I can follow it all fine including the integration after that section it's just the inbetween that I can't seem to get my head around! Any help would be greatly appreciated!

Homework Equations


Worked integration of da/(27.84 x 10^-6 x a^1.5) from 4 x 10^-3 to 10 x 10^-3 m, rewritten as 3.592 x 10^4 times the integral of a^-1.5 da, giving Nf = 4.174 x 10^5 cycles.


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  • Worked integration of da/(27.84 x 10^-6 x a^1.5) from 4 x 10^-3 to 10 x 10^-3 m, rewritten as 3.592 x 10^4 times the integral of a^-1.5 da, giving Nf = 4.174 x 10^5 cycles.
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PCal said:
1. The problem statement, all given data
I've been working through one of the lessons for my HNC and I'm totally stuck on how they got from 27.84x10^-6 to 3.593x10^4.

They may have used the ##1/x## button on a calculator!
 
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PeroK said:
They may have used the ##1/x## button on a calculator!
Yesss! Thank you!
 
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