Here is an alternative approach to handling absolute value terms as the decision variables: abs(x) is the smallest value z that satisfies x [itex]\leq[/itex] z and -x [itex]\leq[/itex] z. Using this,convert the following into a lp
Min 2x1 + 3abs(x2)
S.T x1 + x2 [itex]\geq[/itex] 6
Here is a pretext from my textbook that shows how to do it a different way
The Attempt at a Solution
After a while of staring at it ,I gave it a try
What do you guys think?
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