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## Homework Statement

Here is an alternative approach to handling absolute value terms as the decision variables: abs(x) is the smallest value z that satisfies x [itex]\leq[/itex] z and -x [itex]\leq[/itex] z. Using this,convert the following into a lp

Min 2x

_{1}+ 3abs(x

_{2})

S.T x

_{1}+ x

_{2}[itex]\geq[/itex] 6

## Homework Equations

Here is a pretext from my textbook that shows how to do it a different way

## The Attempt at a Solution

After a while of staring at it ,I gave it a try

What do you guys think?

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