Solve Absolute Values: z∈C |z - 1| = 5, |z - 4| = 4, |4 - z2| = z

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Homework Help Overview

The discussion revolves around solving two problems involving absolute values in the complex number domain. The first problem requires finding all complex numbers z such that |z - 1| = 5 and |z - 4| = 4. The second problem involves determining z such that |4 - z²| = z.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • The original poster attempts to express z in terms of its real and imaginary components and derives equations based on the absolute value definitions. They express uncertainty about their solution for the first problem and seek guidance for the second problem, questioning how to proceed given that the absolute value must yield a real number.

Discussion Status

Some participants confirm the correctness of the original poster's solution for the first problem. Guidance is offered regarding the nature of absolute values in the second problem, prompting further exploration of the conditions under which z can be defined. Multiple interpretations regarding the solutions are being discussed, particularly concerning the validity of roots derived from the equations.

Contextual Notes

Participants note that z must be non-negative as it is defined in relation to an absolute value, which influences the acceptable solutions for the second problem. There is also mention of constraints regarding the nature of roots derived from second-order equations.

Hannisch
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Homework Statement


So I've got two problems I'm struggling a bit with. One of them I've solved (I think), but I'm definitely not sure. The other one is bugging me a bit. Anyway:

i] Determine all z∈C so that |z - 1| = 5 and |z - 4| = 4

ii] Determine all z∈C so that |4 - z2| = z


Homework Equations





The Attempt at a Solution


i] I say that z = x+yi as a starting point. From there:

|x + yi -1| = 5
√( (x - 1)2 + y2 ) = 5
x2 + 1 -2x +y2 = 25

|x + yi -4| = 4
√( (x-4)2 + y2 ) = 4
x2 + 16 - 8x + y2 = 16

y2 = 8x - x2

Inserting this in the first equation:

x2 + 1 - 2x + 8x - x2 = 25

6x + 1 = 25

x = 4

and then y2 = 32 - 16 = 16, y = ± 4

So I get z = 4±4i

I think this should be correct, but I'm a bit.. unsure.


ii] I've gotten so far that I've looked at the exercise and realized that the absolute value of something is always a real number, which means if z = x+yi, then y=0. But from here I'm unsure on how to proceed.

How on Earth am I supposed to solve this? I'm feeling.. lost.
 
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i] is correct.

ii] You are right, z is real. How do you define the absolute value of a real number?

ehild
 
The only thing I can think of right now (it's.. late) is:

|x| = x if x>0
|x| = 0 if x=0
|x| = -x if x<0

Is this what you mean?
 
Never mind, I had a insight today during my lecture and suddenly it was all very, very clear and the answers are something like ±(1 + √17)/2

Thanks though!
 
Almost good! Do not forget that z can not be negative as it is equal to an absolute value. You had two second order equations, with 4 roots altogether, but only the positive roots are valid. (±1 + √17)/2

ehild
 
Yeah, sorry, I put the plus/minus sign wrong :) I figured that out and even checked if they were in the right intervals and such.
 

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