Converting a log equation to exponential equation

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Homework Help Overview

The discussion revolves around converting a logarithmic equation, specifically f(x) = log5(x) + 3, into its exponential form. Participants are exploring the relationship between logarithmic and exponential functions within the context of graphing the equation.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss how to express the logarithmic equation in exponential form and question how to isolate x in the resulting equation. There are attempts to clarify the conversion process and the implications of the logarithmic definition.

Discussion Status

The discussion is ongoing, with participants sharing insights and attempting to clarify the conversion between forms. Some guidance has been provided regarding the exponential representation, but there is still exploration of how to manipulate the equation further.

Contextual Notes

There is mention of uncertainty regarding the appropriate section for the question, as well as a note about the use of LaTeX for mathematical expressions. Participants are also addressing the need to express the equation in a specific format for graphing purposes.

wScott
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Homework Statement


the question asks to graph the equation:
(don't know how to use latex sorry)
f(x) = log5 (x) + 3 where the 5 is the base
Just for my curiosity what would the exponential equation be?
I can graph it, just can't get the exponential form
Tell me if this should go in the general math section.
 
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You already put it in the general math section lol, look there for the working.
[tex]5^{f(x)} = 125x[/tex]
 
Can that be expressed as x=? and can you show me how you did that?
 
wScott said:

Homework Statement


the question asks to graph the equation:
(don't know how to use latex sorry)
f(x) = log5 (x) + 3 where the 5 is the base
Just for my curiosity what would the exponential equation be?
I can graph it, just can't get the exponential form
Tell me if this should go in the general math section.

"Solve" for x: y- 3= log5(x) so, using the definition of log5(x) as the inverse of 5x, x= 5y-3= (1/125)5y.
 

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