Switching between exponential and logarithmic form

wScott
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Hello you bunch of owls, I'm doing my homework at the moment and I'm curious, how woul I express the logarithmic equation

f(x) = log5 (x) + 3 in it's exponential form (where 5 is the base).

This isn't part of the homework, I'm just supposed to graph it, but I'm curious as to what the exponential form looks like.
 
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5^{f(x)} = 5^{\log_5 x +3} = 5^{\log_5 x} \cdot 5^3<br /> =125x
 
Umm, I'm sure you're right, but could you elaborate on why that's correct? Could you explain how you got that i mean.

And is there a x= form of that, that's what I'vebeen trying to come up with :p.
 
Can anyone explain this please? Or atleast tell me what to google to find out why this works?
 
Well say I have something equal to each other. a=b.

Then x^a is equal to x^b, since a=b. So in this case, f(x)=log_5 x + 3, I did
5^(log_5 x+3) = 5^(f(x)), and I reversed the rule a^ma^n=a^{m+n} on the 5^(log_5 x +3 ) and there we go :)

And you trying to make it equal x?
5^3x=5^{f(x)}
x=5^{f(x)-3}
 
Ahh, alright, thank you very much Sir :)
 
Thats alright, but please don't call me sir. I am 15 years old lol, Sir makes me feel like I am 40 >.<"

EDIT: Not that there's anything wrong with being 40 !:P

EDIT 2: ..OR OLDER...damn political correctness..
 
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Could you tell me how you came up with 125x?

P.S.:haha
 
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5^{f(x)} = 5^{\log_5 x +3} = 5^{\log_5 x} \cdot 5^3<br />. You should be able to follow that so far. Now, by definiton of the logaritim, a^{\log_a x} =x. And 5^3 is just 125 by expanding it..
 
  • #10
Okay, thanks a bunch:)
 
  • #11
wScott said:
Could you tell me how you came up with 125x?

P.S.:haha

53=125

/*extra characters*/

EDIT: I guess Gib Z beat me to it.
 
  • #12
Lol just 16 minutes late d_leet :P
 
  • #13
Gib Z said:
Lol just 16 minutes late d_leet :P

Eh, it's been a long day.
 
  • #14
loga(x) and ax are inverse functions.
If y= loga(x) then x= ay and vice-versa.
 
  • #15
here you go with graph >

http://img123.imageshack.us/img123/6964/untitledfy8.jpg

ps: the graph would be something like that but not exactly .

:zzz:
 
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