Converting a Third-Order Differential Equation into a Vector System?

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johnaphun
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Homework Statement



Convert the differential equation for x,

x''' + 2(x''2) = 0

Into a system of first order differential equations. Put the system in vector form

Homework Equations





The Attempt at a Solution



I'm able to do this for simpler DE's but I can't seem to find an answer for this one. Do i need to do anything different because of the 3rd derivative?
 
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Same thing except that I tend to prefer to use letters near the beginning of the alphabet, like "a", to represent constants, letters near the end, like "x", to represent variables.

Since your equation is [itex]x'''+ 2(x'')^2= 0[/itex], let y= x' and z= y'= x'' so that x'''= z'. Now, [itex]x'''+ 2(x'')^2= z'+ 2z^2= 0[/itex], [itex]y'= z[/itex], and [itex]x'= y[/itex].
 
HallsofIvy said:
Same thing except that I tend to prefer to use letters near the beginning of the alphabet, like "a", to represent constants, letters near the end, like "x", to represent variables.

Normally, I'd agree! :smile: … but this equation looked to me like a dynamical equation, with x being distance, so I preferred the familiar form of x' = v, v' = a. :wink: