Converting a Third-Order Differential Equation into a Vector System?

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Homework Help Overview

The problem involves converting a third-order differential equation, specifically x''' + 2(x''^2) = 0, into a system of first-order differential equations and expressing that system in vector form.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to apply methods used for simpler differential equations but expresses uncertainty regarding the third derivative. Some participants suggest defining new variables to simplify the equation, such as letting a = x'' and v = x'. Others propose using different variable representations to clarify the relationships between derivatives.

Discussion Status

Participants are exploring various ways to approach the conversion of the differential equation. Some guidance has been offered regarding variable substitutions, but there is no explicit consensus on a single method or solution yet.

Contextual Notes

The discussion reflects differing preferences in variable naming conventions and interpretations of the equation's context, which may influence the approach taken.

johnaphun
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Homework Statement



Convert the differential equation for x,

x''' + 2(x''2) = 0

Into a system of first order differential equations. Put the system in vector form

Homework Equations





The Attempt at a Solution



I'm able to do this for simpler DE's but I can't seem to find an answer for this one. Do i need to do anything different because of the 3rd derivative?
 
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hi johnaphun! :smile:

what's the difficulty? :confused:

put a = x'' and solve, then put v = x' and solve
 
Same thing except that I tend to prefer to use letters near the beginning of the alphabet, like "a", to represent constants, letters near the end, like "x", to represent variables.

Since your equation is x'''+ 2(x'')^2= 0, let y= x' and z= y'= x'' so that x'''= z'. Now, x'''+ 2(x'')^2= z'+ 2z^2= 0, y'= z, and x'= y.
 
HallsofIvy said:
Same thing except that I tend to prefer to use letters near the beginning of the alphabet, like "a", to represent constants, letters near the end, like "x", to represent variables.

Normally, I'd agree! :smile: … but this equation looked to me like a dynamical equation, with x being distance, so I preferred the familiar form of x' = v, v' = a. :wink:
 

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