Converting a value material parameter

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SUMMARY

The discussion focuses on converting the modulus of elasticity (E) from a given equation, specifically 109/E = 80/psi, into psi units. The correct manipulation of the equation leads to E being expressed as 1.25 x 107 psi. Participants emphasized the importance of including the unit being converted from for clarity and accuracy in unit conversions. A more efficient method for solving the equation was also provided, highlighting the use of reciprocals in fraction manipulation.

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  • Understanding of modulus of elasticity in material science
  • Familiarity with unit conversion techniques
  • Basic algebraic manipulation skills
  • Knowledge of dimensional analysis
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  • Learn about modulus of elasticity in different materials
  • Explore dimensional analysis techniques for engineering problems
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Students in engineering or physics, material scientists, and professionals involved in mechanical design or structural analysis will benefit from this discussion.

fred_91
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Homework Statement



I have E as a material parameter. It is a modulus of Elasticity It is given as:
109/E = 80/psi

I want to write E as a value with units psi.

Homework Equations

The Attempt at a Solution


Is this correct?

1/E = 80*109/psi
So
psi/E = 80*109
So
E = 1.25*10^7 psi
 
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Mentor note: Thread moved from Calculus section
fred_91 said:

Homework Statement



I have E as a material parameter. It is a modulus of Elasticity It is given as:
109/E = 80/psi

I want to write E as a value with units psi.

Homework Equations

The Attempt at a Solution


Is this correct?

1/E = 80*109/psi
So
psi/E = 80*109
So
E = 1.25*10^7 psi
Looks fine to me, although your problem description omits some information. Apparently you're converting from some kind of units to PSI. Since you're converting between two kinds of units, you should include the unit you're converting from, not just the one you're converting to.
Your equation looks weird with "psi" ujits on one side, and no units shown on the left side.

A quicker way than you found is this:
If ##\frac {10^9} E = \frac {80}{\text{psi}}##
then ##\frac E {10^9} = \frac{\text{psi}} {80}## -- if two fractions are equal, then their reciprocals are also equal (providing neither fraction is 0)
Now multiply both sides by ##10^9## and simplify a bit.
 

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