Converting Functions from x to y

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Homework Help Overview

The discussion revolves around converting functions expressed in terms of x into functions expressed in terms of y, specifically focusing on the function y = x^2 - 5x. Participants are exploring the implications of finding inverse functions and the challenges posed by the nature of quadratic functions.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the process of finding inverse functions and the complications that arise due to the non-one-to-one nature of quadratic functions. There is mention of completing the square as a method to express x in terms of y.

Discussion Status

The conversation is ongoing, with some participants providing insights into the challenges of inverting quadratic functions and the necessity of restricting the domain to achieve a one-to-one function. Others are reflecting on the complexity of the task.

Contextual Notes

There is an acknowledgment that the original functions are not one-to-one, which complicates the inversion process. The discussion highlights the need to consider the implications of even powers in functions when attempting to find inverses.

ozone
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I just need help turning a function of x into a function of y.

I'll give you an example and maybe you can explain it and expand upon the idea.

Thanks in advance.

y = x^2 -5x (see a very simple function! I just can't figure out how to convert it).

or y = x^2 - 2x
 
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ozone said:
I just need help turning a function of x into a function of y.

I'll give you an example and maybe you can explain it and expand upon the idea.

Thanks in advance.

y = x^2 -5x (see a very simple function! I just can't figure out how to convert it).

or y = x^2 - 2x
What you're asking is not clear, but I think you are talking about finding the inverse function. In your first example, y = f(x) = x2 - 5x. Here y is a function of x. It is not, however, a one-to-one function, so the inverse will not be a function.

To solve for x in terms of y, complete the square.
y = x2 - 5x
==> y = x2 - 5x + (5/2)2 - (5/2)2 = (x - 5/2)2 - (5/2)2

Can you take it from there?

To make the inverse a function, restrict the domain of the original function to make it one-to-one.
 
Beware, however: your function y = x2 - 5x (the graph of which is a parabola) assigns two different values of x to the same value of y . So when you "invert" this to get x = "something" , you will get a plus-or-minus sign, which tells us that we get back two functions of y , each corresponding to half of the original parabola.

This is always a problem with even powers of x in a function; reversing the direction to return from y to x gives two possible values of x which could have led to that value of y , and a "rule" which assigns one value of y to two values of x is NOT a function. That's why we need to split your result into two parts. (We don't have this problem with odd powers of x .)
 
Thank you for your answers.
Yes I was looking to complete the square, and now that I've seen this it is quite a bit more complicated then I expected.
 

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